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3 years ago

How many moles and atoms are there in 60 grams of Calcium?

Chemistry

2 answers:

mars1129 [50]3 years ago

8 0

Answer:

In 60 grams there are 1,5 mols

Explanation:

marta [7]3 years ago

6 0

Answer:

The moles present in 60 g of calcium are 1.5 moles.

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Given that:2NO (g)→N2 (g)+O2 (g)N2 (g)+O2 (g)+Cl2 (g)→2NOCl (g) has an enthalpy change of −180.6 kJ has an enthalpy change of 10

likoan [24]

Answer:

Explanation:

It is possible to answer this question knowing Hess's law that says you can sum half-reactions enthalpy cahnge to obtain enthalpy change of the total reaction. Using the reactions:

(1) 2NO(g) → N₂(g)+O₂(g) ΔH = -180,6 kJ

(2) N₂(g) + O₂(g) + Cl₂(g) → 2NOCl(g) ΔH = +103,4 kJ

The reverse reactions of (1) and (2) are:

N₂(g)+O₂(g) → 2NO(g) ΔH = +180,6 kJ

2NOCl(g) → N₂(g) + O₂(g) + Cl₂(g) ΔH = -103,4 kJ

The sum of these reactions is:

2NOCl(g) → 2NO(g) + Cl₂(g) ΔH = +180,6 kJ -103,4 kJ = 77,2 kJ

I hope it helps!

6 0

2 years ago

The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17x103L/mol/cm. Calculate the linear range of phenol conce

Scilla [17]

Explanation:

The given data is as follows.

$\lambda$ = 211 nm, $\sum = 6.17 \times 10^{3} mol/L/cm$

l = 1 cm, 7% < Transmittance < 85%

Suppose the aqueous solution follows Lambert-Beer's law. Therefore,

Absorbance = $-log \frac{\text{Percentage transmittance}}{100}$

Hence, for 7% transmittance the value of absorbance will be as follows.

Absorbance = $-log \frac{7}{100}$

$A_{1}$ = 1.155

For 85% transmittance the value of absorbance will be as follows.

Absorbance = $-log \frac{85}{100}$

$A_{2}$ = 0.07058

According to Lambert-Beer's law.

A = $\sum \times l \times C$

where, A = absorbance

$\sum$ = molar extinction coefficient

C = concentration

Therefore, concentration for 7% absorbance is as follows.

$A_{1} = \sum \times l \times C_{1}$

$C_{1}$ = $\frac{1.155}{6.17 \times 10^{3} \times 1}$

= $0.187 \times 10^{-3} mol/L$

= 0.187 mmol/L

Concentration for 85% absorbance is as follows.

$A_{2} = \sum \times l \times C_{2}$

$C_{2}$ = $\frac{0.07058}{6.17 \times 10^{3} \times 1}$

= $0.01144 \times 10^{-3} mol/L$

= 0.01144 mmol/L

Thus, we can conclude that linear range of phenol concentration is 0.01144 mmol/L to 0.187 mmol/L.

6 0

3 years ago

Pleaseeeeee hellllllpppp

Yakvenalex [24]

Im pretty Sure its B Tuesday And Wensday

4 0

3 years ago

Read 2 more answers

The magnitude of an earthquake, measured on the Richter Scale, is M log1o T where / is the amplitude registered on a seismograph

just olya [345]

Answer: The magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

Explanation:

Richter scale is defined as the scale which expresses the magnitude of earthquake on the basis of the seismograph oscillations.

The equation used to measure the magnitude of an earthquake on Richter scale is:

$M=log_{10}\frac{I}{I_o}$

where

I = amplitude registered on seismograph 100 km away from seismic center = $10,000,000I_o$

$I_o$ = small amplitude

Putting values in above equation, we get:

$M=\log_{10}(\frac{10000000I_o}{I_o})\\\\M=7$

Hence, the magnitude rating for an earthquake causing an amplitude 10,000,000 times $I_o$ is 7.

8 0

3 years ago

How many moles of CF4 can be produced when 8.95 mol C reacts with 7.88 mol F2?

Molodets [167]

The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.

<h3>Reaction between Carbon and Fluorine </h3>

The reaction between carbon and Fluorine is given as;

C + 2F₂ -------> CF₄

1 : 2 1

from the reaction above,

2 moles of F₂ requires 1 mole of C

7.88 mole of F₂ will require: 7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.

The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.

Learn more about moles here: brainly.com/question/15356425

#SPJ1

8 0

2 years ago