C. Model. It's a graphical model that displays one or more weather elements.
This all depends on lots of independent variables such as force used to roll the ball, wind resistance, etc. With no variables included, they would both move at the same velocity.
Data:
<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.
Quesiton: Vapor pressure of water
Solution:
Raoult's Law: </span><span><span>The vapour
pressure of a solution of a non-volatile solute is equal to the vapour
pressure of the pure solvent at that temperature multiplied by its mole
fraction.
Formula: p = Xsolvent * P pure solvent
X solvent = moles solvent / moles of solution
molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol
moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol
molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol
moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol
moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol
Xsolvent = 7.50mol / 7.81mol = 0.960
p = 233.7 torr * 0.960 = 224.4 torr
Answer: 224.4 torr
</span> </span>
Answer:
The yearly release of 
into the atmosphere is 
.
Explanation:
Annual production of CaO = 
Moles of CaO :
According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with 
of CaO moles of carbon-dioxide moles produced will be:
of carbon-dioxide
Mass of 
moles of carbon-dioxide:
The yearly release of into the atmosphere is .
Answer:
71.5 atm
Explanation:
Use Boyle's Law and rearrange formula.
- Hope this helps! Please let me know if you need further explanation.
