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suter [353]
3 years ago
6

PLZZ help me with this I really need your help

Mathematics
2 answers:
Georgia [21]3 years ago
5 0
Basil yum just use ur brain and find out before asking for help, ask ur teacher or somthin
natali 33 [55]3 years ago
5 0

Answer:

1) Linear

2) Slope-intercept form

3) Slope

4) 25

5) Y-intercept

6) 50

7) Y-axis

8) 0

9) Rise

10) Run

11) 1

12) 75

13)line

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The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r
DIA [1.3K]
<span>Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle. 

The representation of the diagram is shown if Figure 1. There's a relationship between </span>sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship. 

a.1 First, find in the diagram a segment whose length is sec θ. 

The segment whose length is sec θ is shown in Figure 2, this length is the segment \overline{OF}, that is, the line in green.

a.2 <span>Explain why its length is sec θ.

We know these relationships:

(1) sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}

(2) </span>cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}
<span>
(3) </span>tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}
<span>
Triangles </span>ΔOFC and ΔOBD are similar, so it is true that:

\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}<span>

</span>∴ \overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}<span>

b.1 </span>Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment \overline{AR}, that is, the line in pink.

b.2 <span>Use the representation of tangent as a clue for what to show for cotangent. 
</span>
It's true that:

\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}

But:

\overline{SR}=\overline{OA}
\overline{OS}=\overline{AR}

Then:

\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}

b.3  Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment \overline{OR}, that is, the line in green.

3 0
4 years ago
What is the slope of the line graphed below? (PLEASE ANSWER IMMEDIATELY)
Dmitrij [34]

Answer:

-2/-3

Step-by-step explanation:

3 0
3 years ago
15q - 12 = 18 <br>help me pls
Jet001 [13]
The answer is q=15

Hope this helps ya
8 0
3 years ago
Help me plzzzzzzzzzzzzzz
scoray [572]

Answer:

the equation is y=4x+3

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Which equation can be used to find B in the triangle below?
WINSTONCH [101]

9514 1404 393

Answer:

  (b)  tan B = 8/6

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relevant relationships:

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

Then angle B is involved in tangent and cosine relationships this way:

  tan B = 8/6 . . . . . . matches 2nd choice

  cos B = 6/10 . . . . . matches no choices

_____

<em>Additional comment</em>

Both of the offered cosine choices give a cosine value that is greater than 1. The cosine of a real angle is never greater than 1, so those can be rejected immediately.

8 0
3 years ago
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