HELP ME PLEASE I DONT UNDERSTAND! I"LL GIVE BRAINLIEST

Dequan is training for a marathon. He runs 20 miles every 4 days. What is the unit rate for Dequan?

KonstantinChe [14]

Answer:

Dequan walks 5 miles per day.

Step-by-step explanation:

So solve this problem, we just need to divide 20 miles by 4 days.

20 ÷ 4 = 5

Therefore, Dequan walks 5 miles per day.

Hope this helps! :D

5 0

2 years ago

Read 2 more answers

Use decimals and fractions in the same equation showing the Commutative Property. Repeat for the Associative Property.

Anna71 [15]

For Commutative Property of Addition

Let us take a decimal number $2.14$ and a fraction $\frac{5}{20}$

Now, according to the Commutative property of Addition:

For any two numbers $a$ and $b$ :

$a+b = b+a$

So, for $2.14$ and $\frac{5}{20}$

Let us add

$2.14+\frac{5}{20} = \frac{214}{100} +\frac{5}{20}$

$=\frac{214}{100} + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100} + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39$

Also,

$\frac{5}{20} + 2.14 = \frac{5}{20} + \frac{214}{100}$

$= \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100} + \frac{214}{100} \\ \\= 0.25 + 2.14 \\ \\ = 2.39$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Commutative Property of Addition is satisfied.

For Associated Property of Addition

Let us take two same decimal numbers $2.14$ , $7.25$ and a fraction $\frac{5}{20}$

Now, according to the Associated property of Addition:

For any three numbers $a$ , $b$ and $c$

$a + (b+c) =(a+b) + c$

So, for $2.14$ , $7.25$ and $\frac{5}{20}$

The Left hand side:

$a + (b+c)$

$2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})$

$= 2.14 + (\frac{725}{100} + \frac{25 }{100})$

$= 2.14 + (\frac{750}{100} )$

$= \frac{214}{100} + \frac{750}{100}$

$= \frac{964}{100}$

$=9.64$

The Right hand side:

$(a + b )+c$

$(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}$

$= 9.39 + \frac{5 \times 5 }{20 \times 5}$

$= 9.39 + \frac{25}{100}$

$= 9.39 + 0.25$

$= 9.64$

Thus,

$(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}$

Therefore, $2.14+\frac{5}{20} = \frac{5}{20} + 2.14$

Hence, Associative Property of Addition is satisfied.

8 0

3 years ago

What do I do? what's Ax??

Liono4ka [1.6K]

$A=\left[\begin{array}{ccc}5&-4\\3&6\end{array}\right] \\\\A_x=\left[\begin{array}{ccc}12&-4\\66&6\end{array}\right]$

$|A_x|=\left|\begin{array}{ccc}12&-4\\66&6\end{array}\right|=(12)(6)-(66)(-4)=72+264=336$

5 0

3 years ago

Simplify. (-2)-3 -8 - 8 user: simplify. 6x-2

Vinvika [58]

If you would like to simplify (-2)-3 -8 - 8 and 6x - 2, you can do this using the following steps:

(-2)-3 -8 - 8 = - 2 - 3 - 8 - 8 = - 5 - 8 - 8 = - 13 - 8 = - 21

6x - 2 = 2 * (3x - 1)

The correct result would be - 21 and 2 * (3x - 1).

3 0

2 years ago

T models the temperature (in degrees Celsius) in New York City when it's t hours after midnight on a given day. Match each state

Klio2033 [76]

Answer:

Please check explanation

Step-by-step explanation:

Here, we want to do a matching.

We shall be matching the given statements with the features we have on the graph

Hence we shall be looking closely at the graph to answer the questions.

The y-intercept is the point at which the graph touches the y-axis

And it was at -3 degrees celsius at the beginning of the day.

The temperature was above zero between 8am and 8pm. The matching statement is that it is increasing or decreasing interval

We can see that the graph rose from 8am before it finally comes to zero at 8pm

Positive or negative interval matches with it was getting warmer between 2am and 2pm.

While temperature was lowest at 2am, we can see a peak at 2pm.

8 0

3 years ago