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Sloan [31]
3 years ago
9

8. When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. I

f 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.
9. If 5.40 kcal of heat is added to 1.00 kg of water at 100⁰C, how much steam at 100⁰C is produced? Show all calculations leading to an answer.
Chemistry
1 answer:
Julli [10]3 years ago
5 0

Hey there!:

8) ΔTb = i*Kb*m  

 m is molality

 Since same number of mol is added to same amount of water in both cases

m will be same for both

is 1 for glucose since it is covalent compound

is 4 of Al(NO3)3 as it breaks into 1 Al₃⁺ and 3 NO₃⁻

So,  ΔTb will be 4 times in aluminum nitrate case

So, boiling point will change by 4ºC


9) use Q = m*  L

L =  heat of vaporization so:

T1=T2=100ºC

5.40 * 1000 => 5400  cal/g

Q =   5400 / 540

Q = 10 grams


Hope that thlps!

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If 2,035 cal of heat is added to a 500.0 g sample of water at 35.0°C, what is the final
Lynna [10]

Answer:

39.1 °C

Explanation:

Recall the equation for specific heat:

q=mc \Delta T\\

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.

You should know that the specific heat of water is 1 cal/g/C.

Using the information in the question:

2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07

The final temperature is about 39.1 °C.

5 0
3 years ago
If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?
Pie

<u><em>Answer:</em></u>

m = \frac{E}{c^2}

c = \sqrt{\frac{E}{m} }

E = 12.8 J

<u><em>Explanation:</em></u>

<u>Part 1: Solving for m</u>

<u>We are given that:</u>

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

m = \frac{E}{c^2}

<u>Part 2: Solving for c</u>

<u>We are given that:</u>

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

c^2 = \frac{E}{m}\\  \\ c=\sqrt{\frac{E}{m}}

<u>Part 3: Solving for E</u>

<u>We are given that:</u>

m = 80 and c = 0.4

<u>To get the value of E, we will simply substitute in the given equation: </u>

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0
3 years ago
I will not stop asking until someone answer hurry up already
Reil [10]

Answer:

Gravity.

Explanation:

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Which of the following acids do NOT ionize completely in solution? Check all that apply.
KIM [24]
<span>The following acids do NOT ionize completely in solution because they are not strong acids are as follows:
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5 0
3 years ago
What is the isotopic symbols for <br> Beryllium atom that contains 9 nucleon?
nadya68 [22]

Answer:

Beryllium-9 is the isotope of beryllium with relative atomic mass 9.

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