Answer:
dttydghcghcghdytdftygfvghxk,ghc
Explanation:
Answer:

Explanation:
Given:
height above which the rock is thrown up, 
initial velocity of projection, 
let the gravity on the other planet be g'
The time taken by the rock to reach the top height on the exoplanet:
where:
final velocity at the top height = 0 
(-ve sign to indicate that acceleration acts opposite to the velocity)

The time taken by the rock to reach the top height on the earth:



Height reached by the rock above the point of throwing on the exoplanet:

where:
final velocity at the top height = 0 


Height reached by the rock above the point of throwing on the earth:



The time taken by the rock to fall from the highest point to the ground on the exoplanet:
(during falling it falls below the cliff)
here:
initial velocity= 0 



Similarly on earth:

Now the required time difference:


Answer:
D = 4 m
Explanation:
Speed of cart in air track v₁ = 0.5 m/s
Speed of cart moved when air is turned off v₂= 1 m/s
The distance travelled by the cart is d₁ = 1 m
Work done (W) = F x d
Work done is equal to the kinetic energy
F x d = 1/2mv²
velocity is directly proportional to distance
therefore,
v₁²/ v₂² = d₁ / d₂
d₂ = d₁v₂² / v₁²
= 1 m x (1 m /s)² / (0.5 m/s)²
= 4 m
Answer:
b. 29.2 rev/min
Explanation:
- Assuming no external torques acting during the process, total angular momentum must be conserved, as follows:

- The initial angular momentum L₀, can be expressed as follows:

where I₀ = initial moment of inertia = moment of inertia of the disk +
moment of inertia of the cylinder and ω₀ = initial angular velocity =
30.0 rev/min.
- Replacing by the values, we get:
⇒ L₀ = I₀* ω₀ = 0.2009 kg*m² * 30.0 rev/min = 6.027 kg*m²*rev/min - The final angular momentum can be written as follows:

where If = final moment of inertia = moment of the inertia of the solid
disk + moment of inertia of the clay flattened on a disk, and ωf = final
angular velocity.
- Replacing by the values, we get:

⇒ Lo =Lf = If*ωf
- Replacing (2) in (1), and solving for ωf, we get:
