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Nuetrik [128]
3 years ago
12

A powerboat, starting from rest maintains a constant acceleration. After a certain time Δt, its displacement and velocity are Δr

and Δv. At time 2Δt, what will be its displacement and velocity, assuming the acceleration remains constant?
(A) 2Δr and 2Δv
(B) 2Δr and 4Δv
(C) 4Δr and 2Δv
(D) 4Δr and 4Δv
Physics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

The correct option is C) 4Δr and 2Δv

Explanation:

Initially from rest means , initial velocity and displacement is zero.

AT time t = Δt ,

Displacement ( s ) = Δr

velocity ( v) = Δv

Now At t = 2Δt

By using the equation of motion

v = u + at

s = ut + ( 1/2)at²

Here ,

v ∝ t   and s ∝ t²

Increasing times by two time velocity will increase twice and displacement by four times

Displacement = 4Δr

Velocity = 2Δv

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A 0.73-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar
Tasya [4]

Answer:

A)  B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West

Explanation:

A) For this exercise we must use the expression of Faraday's law for a moving body

            fem = -  \frac{d \phi }{dt}

            fem = - \frac{d (B l y}{dt}= - B l v- d (B l y) / dt = - B lv

            B = - \frac{fem}{l \ v}

we calculate

             B = - 7.9 10⁻⁴ /(0.73 20)

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B) to determine which side of the bar is positive, we must use the right hand rule

the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.

Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West

4 0
3 years ago
When Bella pushes a box with a mass of 5.25 kilograms with a force of 15.75 newtons, it accelerates at a rate of 2.5 meters/seco
Mariana [72]

Sure !

Start with Newton's second law of motion:

                     Net Force = (mass) x (acceleration) .

This formula is so useful, and so easy, that you really
should memorize it.

Now, watch:

The mass of the box is 5.25 kilograms, and the box is
accelerating at the rate of  2.5 m/s² .
What's the net force on the box ?

                    Net Force = (mass) x (acceleration)

                                     = (5.25 kilograms) x (2.5 m/s²)

                     Net force =       13.125 newtons .

But hold up, hee haw, whoa !  Wait a second !
Bella is pushing with a force of 15.75 newtons, but the box
is accelerating as if the force on it is only 13.125 newtons.
What happened to the rest of Bella's force ? ?

==>  Friction is pushing the box in the opposite direction,
and cancelling some of Bella's force.

How much ?

            (Bella's 15.75 newtons) minus (13.125 that the box feels)

           =      2.625 newtons backwards, applied by friction.


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3 years ago
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3 years ago
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max2010maxim [7]
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Choice-d says this.
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3 years ago
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