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Nuetrik [128]
3 years ago
12

A powerboat, starting from rest maintains a constant acceleration. After a certain time Δt, its displacement and velocity are Δr

and Δv. At time 2Δt, what will be its displacement and velocity, assuming the acceleration remains constant?
(A) 2Δr and 2Δv
(B) 2Δr and 4Δv
(C) 4Δr and 2Δv
(D) 4Δr and 4Δv
Physics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

The correct option is C) 4Δr and 2Δv

Explanation:

Initially from rest means , initial velocity and displacement is zero.

AT time t = Δt ,

Displacement ( s ) = Δr

velocity ( v) = Δv

Now At t = 2Δt

By using the equation of motion

v = u + at

s = ut + ( 1/2)at²

Here ,

v ∝ t   and s ∝ t²

Increasing times by two time velocity will increase twice and displacement by four times

Displacement = 4Δr

Velocity = 2Δv

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Answer:

Volume of balloon =  1000 cm^3

Explanation:

 The head of a normal person can be assumed as a sphere with radius 10 cm.

 Volume of sphere =\frac{4}{3} \pi r^3, where r is the radius.

 We have approximate radius = 10 cm.

  Approximate volume of head =\frac{4}{3} \pi r^3=\frac{4}{3} *\pi* 10^3=4188cm^3

 In the given options the closest value to the approximate volume is 1000 cm^3.

 So, volume of head = Volume of balloon =  1000 cm^3

4 0
3 years ago
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A because an earthquake is shaking of tectonic plates
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A square plate of side 9 m is submerged in water at an incline of 60∘ with the horizontal. Its top edge is located at the surfac
Tpy6a [65]

Answer:

The force on one side of  the plate is 3093529.3 N.

Explanation:

Given that,

Side of square plate = 9 m

Angle = 60°

Water weight density = 9800 N/m³

Length of small strip is

y=\dfrac{\Delta y}{\sin60}

y=\dfrac{2\Delta y}{\sqrt{3}}

The area of strip is

dA=\dfrac{9\times2\Delta y}{\sqrt{3}}

We need to calculate the force on  one side of  the plate

Using formula of pressure

P=\dfrac{dF}{dA}

dF=P\times dA

On integrating

\int{dF}=\int_{0}^{9\sin60}{\rho g\times y\times 6\sqrt{3}dy}

F=9800\times6\sqrt{3}(\dfrac{y^2}{2})_{0}^{9\sin60}

F=9800\times6\sqrt{3}\times(\dfrac{(9\sin60)^2}{2})

F=3093529.3\ N

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7 0
3 years ago
As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.33 m l
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Answer: 62 μT

Explanation:

Given

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Velocity of rod, v = 3.19 m/s

Induced emf, e = 0.263*10^-3 V

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e = blv where,

e = induced emf of the rod

b = magnetic field of the rod

l = length of the rod

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b = 0.263*10^-3 / 4.2427

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8 0
3 years ago
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