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natta225 [31]
3 years ago
5

Light travels through a liquid at 2.25e8 m/s. What is the index of refraction of the liquid?

Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

The index of refraction of the liquid is n = 1.33 equivalent to that of water

Explanation:

Solution:-

- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.

- The index of refraction is material property and proportional to density of the material.

- The denser the material the slower the light will move through associated with considerable diffraction angles.

- The lighter the material the faster the light pass through the material without being diffracted as much.

- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.

- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.

- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.

- The light passes through a liquid with speed v = 2.25*10^8 m/s :

                         n = c / v\\\\n = \frac{ 3*10^8 }{2.25*10^8} \\\\n = 1.33

- The index of refraction of the liquid is n = 1.33 equivalent to that of water.    

         

ladessa [460]3 years ago
6 0

Answer:

Refractive index = 1.33

Explanation:

Refractive index is of a material explains how light passes through a medium. It is the ratio of speed of light in vacuum to the speed of light in the medium.

We know the speed of light in water is 2.25* 10^8 and there is a change iñ speed of light in every medium it passes (except when it passes through vacuum). The change in speed of light is known to be = 2.99*10^8

Given speed of light = 2.25*10^8 m/s

Formula for refractive index:

n = \frac{c}{v}

Where,

change in speed of light, c= 2.99*10^8

speed of light, v = 2.25*10^8 m/s

Refractive index, n = \frac{2.99*10^8}{2.55*10^8}

= 1.328

= 1.33

The liquid is water, and the index of refraction of water is 1.33

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someone help pls. Two students, Mia and Peter, leave school to meet at the local coffee shop. Peter decides to jog to the coffee
cluponka [151]

Answer:

1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km

2) Mia's average speed is 6.00 km/hour

Peter's average speed is 8.48 km/hour

4) Mia's average velocity = Peter's average velocity = 6.00 km/hour

Explanation:

The given information from the diagram are;

The distance Peter jogs from school to the flower shop = 2.00 km

The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.

The distance Mia walks from school directly to the Coffee shop = 3.00 km

The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour

1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km

The distance Mia travels from school to the Coffee shop = 3.00 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km

2) Average \ speed = \dfrac{Total \ distance \ traveled}{Total \ time \ taken \  in \ the \ journey}

Therefore, \ Mia's \ average \ speed = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Mia's average speed = 6.00 km/hour

Peter's \ average \ speed = \dfrac{4.24 \ km}{0.5 \ hour}= 8.48 \ km/hour

Peter's average speed = 8.48 km/hour

4) Average \ velocicty = \dfrac{Displacement }{Time  \ taken}

The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter

The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour

Therefore, \ Mia's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Mia's average velocity = 6.00 km/hour

Peter's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Therefore, Peter's average velocity is also = 6.00 km/hour

6 0
3 years ago
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