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natta225 [31]
3 years ago
5

Light travels through a liquid at 2.25e8 m/s. What is the index of refraction of the liquid?

Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0

Answer:

The index of refraction of the liquid is n = 1.33 equivalent to that of water

Explanation:

Solution:-

- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.

- The index of refraction is material property and proportional to density of the material.

- The denser the material the slower the light will move through associated with considerable diffraction angles.

- The lighter the material the faster the light pass through the material without being diffracted as much.

- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.

- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.

- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.

- The light passes through a liquid with speed v = 2.25*10^8 m/s :

                         n = c / v\\\\n = \frac{ 3*10^8 }{2.25*10^8} \\\\n = 1.33

- The index of refraction of the liquid is n = 1.33 equivalent to that of water.    

         

ladessa [460]3 years ago
6 0

Answer:

Refractive index = 1.33

Explanation:

Refractive index is of a material explains how light passes through a medium. It is the ratio of speed of light in vacuum to the speed of light in the medium.

We know the speed of light in water is 2.25* 10^8 and there is a change iñ speed of light in every medium it passes (except when it passes through vacuum). The change in speed of light is known to be = 2.99*10^8

Given speed of light = 2.25*10^8 m/s

Formula for refractive index:

n = \frac{c}{v}

Where,

change in speed of light, c= 2.99*10^8

speed of light, v = 2.25*10^8 m/s

Refractive index, n = \frac{2.99*10^8}{2.55*10^8}

= 1.328

= 1.33

The liquid is water, and the index of refraction of water is 1.33

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Read 2 more answers
Temperature and pressure of a region upstream of a shockwave are 295 K and 1.01* 109 N/m². Just downstream the shockwave, the te
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Answer:

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change in enthalapy \Delta H = Cp(T_2 -T_1)

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change in entropy

\Delta S =Cp ln(\frac{T_2}{T_1}) -R*ln(\frac{P_2}{P_1})

\Delta S =1004.5 ln(\frac{800}{295}) -287*ln(\frac{8.74*10^5}{1.01*10^5})

\Delta S = 382.79 J kg^{-1} K^{-1}

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At the start of the 0.266 s, the object's speed was 8.26 m/s.

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