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3 years ago

The Andrews Family bought 2 adult tickets,3 children tickets,and 1 senior

Mathematics

2 answers:

kirill [66]3 years ago

6 0

Answer:

$26.00

Step-by-step explanation:

weqwewe [10]3 years ago

4 0

The total would be $43.50

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Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry . What fraction of th

professor190 [17]

Answer:

The fraction of smoothies sold were either banana or strawberry is $\frac{11}{12}.$

Step-by-step explanation:

Given:

Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry.

Now, to find the fraction of the smoothies sold were either banana or strawberry.

Fraction of smoothie were of banana = $\frac{5}{6} .$

Fraction of smoothie were of strawberry = $\frac{1}{12} .$

Now, to get the fraction smoothies sold were either banana or strawberry by adding both the fractions of banana and strawberry:

$\frac{5}{6} +\frac{1}{12} \\\\=\frac{10+1}{12} \\\\=\frac{11}{12}$

Therefore, the fraction of smoothies sold were either banana or strawberry is $\frac{11}{12}.$

7 0

3 years ago

Please hep me out !!!!!

Volgvan

Answer:

Step-by-step explanation:

Assuming you require the distance between the 2 points.

To calculate the distance d use the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (- 3, - 8) and (x₂, y₂ ) = (- 2, - 3)

d = $\sqrt{(-2+3)^2+(-3+8)^2}$

= $\sqrt{1^2+5^2}$

= $\sqrt{1+25}$

= $\sqrt{26}$ → A

7 0

2 years ago

Solve for the given variable (see pic)

4vir4ik [10]

27+a=32
a=32-27
a=5

Hope this helped you :)

7 0

3 years ago

Read 2 more answers

The nearest 100 of 87682

Nonamiya [84]

The nearest 100 of 87682?
The answer is 600

5 0

3 years ago