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DaniilM [7]
2 years ago
13

Please I need a step by step explanation ASAP.

Mathematics
1 answer:
34kurt2 years ago
5 0

Answer:

38.6 cm

Step-by-step explanation:

add all of the sides up to get your perimeter

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Help :/ ill give brainly :>
olga55 [171]

Answer:

A. Trapezoid

B. Isoclese triangle

c. Equilateral triangle

d. Kite

4 0
3 years ago
Read 2 more answers
How much do you need to subtract from 41/6 to get 6
Svetllana [295]
Well 41 divided by 6 is 6.8333333333333 so you just need to subtract .833333333333

I hope this answered your question
3 0
3 years ago
Point O is the center of the circle.
photoshop1234 [79]

Answer:

28

Step-by-step explanation:

6 0
3 years ago
The general equation for depreciation is given by y=a(1-r)^t where y=current value.
Jlenok [28]

With the help of the given equation, we know that the automobile is worth $12528.15 after four years.

<h3>What are equations?</h3>
  • A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
  • a formula that expresses the connection between two expressions on each side of a sign.
  • Typically, it has a single variable and an equal sign.
  • Like this: 2x - 4 Equals 2.
  • In the above example, the variable x exists.

So, the equation of depreciation: y = A(1 - r)∧t

The current value is y.

A is the initial cost.

r is the depreciation rate.

t is the time in years, and

In four years, we must ascertain the present value.

Now,

y = $24000(1 - 0.15)⁴

y = 24000(0.85)⁴

y = 24000 × 0.52200625

y = 12528.15

Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.

Know more about equations here:

brainly.com/question/28937794

#SPJ4

Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $

8 0
1 year ago
The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g
andrezito [222]

I'll denote the identity function by \mathrm{Id}. Then for any functions f with inverse f^{-1},

\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}

One important fact is that composition is associative, meaning for functions f,g,h, we have

(f\circ g)\circ h=f\circ(g\circ h)

So given

h=f\circ g

we can compose the functions on either side with g^{-1}:

h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})

then apply the rules listed above:

h\circ g^{-1}=f\circ\mathrm{Id}=f

3 0
3 years ago
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