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Schach [20]
2 years ago
9

Nemistry I sem

Chemistry
1 answer:
GaryK [48]2 years ago
3 0

Answer:

A

Explanation:

BF3 has a trigonal planar shape.

XeO3 has a trigonal pyramidal shape.

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Why can't astronomers take a picture of a black hole?
san4es73 [151]

Answer:

Gravity is so strong that even light cannot escape a black hole.

Explanation:

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3 years ago
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2Al + 6HCl --> 2AlCl3 + 3H2 Aluminium reacts with hydrochloric acid. How many grams of aluminum are necessary to produce 11 L
dem82 [27]

Answer:

8.8g of Al are necessaries

Explanation:

Based on the reaction, 2 moles of Al are required to produce 3 moles of hydrogen gas.

To solve this question we must find the moles of H2 in 11L at STP using PV = nRT. With these moles we can find the moles of Al required and its mass as follows:

<em>Moles H2:</em>

PV = nRT; PV/RT = n

<em>Where P is pressure = 1atm at STP; V is volume = 11L; R is gas constant = 0.082atmL/molK and T is absolute temperature = 273.15K at STP</em>

Replacing:

1atm*11L/0.082atmL/molK*273.15K = n

n = 0.491 moles of H2 must be produced

<em />

<em>Moles Al:</em>

0.491 moles of H2 * (2mol Al / 3mol H2) = 0.327moles of Al are required

<em />

<em>Mass Al -Molar mass: 26.98g/mol-:</em>

0.327moles of Al * (26.98g / mol) = 8.8g of Al are necessaries

7 0
3 years ago
Simply parmanent tissue real life application please help it's for my project ​
WITCHER [35]
The simple tissues are parenchyma, sclerenchyma and collenchyma. Chlorenchyma is a parenchyma, having chloroplast. It is a simple permanent tissue, having chloroplast.
8 0
3 years ago
How do you know when a chemical equation is balanced?
kirza4 [7]

Both sides of the equation would be equal.

Hope This Helps You!

6 0
3 years ago
A 1.0 L volume of gas at 27.0°C exerts a pressure of 85.5 K PA what will the pressure be at 127°C assume constant volume
Marianna [84]

Answer:

114 kPa

Explanation:

Using Gay-Lussac's law you get the equation \frac{P1}{T1} x \frac{P2}{T2} and converting celcius you get the final equation of \frac{85.5}{27+273}  x \frac{P2}{127+273} . After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa

4 0
2 years ago
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