Question

A newspaper story describing the local celebration of Mole Day on October 23 (selected for Avogadro's number, 6.02 X 10^ 23 ) attempting to give the reader a sense of the size of the number by stating that a mole of M&Ms would be equal to 18 tractor trailers full. Assuming that an M&M occupies the volume of about 0.5 cm ^ 3 calculate the dimensions of a cube required to hold one mole of M&Ms. Would 18 tractor trailers be sufficient?

Answer 1

Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one  M & M= 0.5 \ cm^3\\\\

M&M 1 mole$= 6.02 \times 10^{23}$

Calculating volume of M& M mole$= 0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3$

Calculating the cube mole$L^3= 3.01 \times 10^{23}\ cm^3$

$L=6.70176 \times 10^{7}\ cm$

   $=6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km$

Therefore 18 tractor trailers wouldn't be sufficient.