1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KIM [24]
3 years ago
14

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut

ion containing 0.75 grams of copper (II) chloride. A single replacement reaction takes place. Which statement explains the maximum amount of copper that the chemist can extract using this reaction? Unbalanced equation: CuCl2 + Al → AlCl3 + Cu Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant Approximately 1.8 grams, because copper (II) chloride acts as a limiting reactant Approximately 0.36 grams, because aluminum acts as a limiting reactant Approximately 1.8 grams, because aluminum acts as a limiting reactant
Chemistry
2 answers:
Y_Kistochka [10]3 years ago
8 0
So would you say that less than 5.3 g of copper II is formed and some aluminum is left in the reaction mixture? Aluminium is the limiting reactant meaning all of it is consumed in the reaction. Only copper chloride is in excess and hence some of it remain in solution.
Allisa [31]3 years ago
4 0
I really need help on this
You might be interested in
Now if your lab partner determined that there were 1.552 x 1022 atoms of H in an unknown sample of C2H4Cl2, how many milligrams
STALIN [3.7K]
To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:

1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>
3 0
4 years ago
Which statement is true about HCI?
katen-ka-za [31]

Answer:

d- it is an acid because it increases the concentration of hydronium ions

Explanation:

HCl; hydrochloric acid is an acid because it increases the concentration of hydronium ions when in solutions.

An acid is a substance that interacts with water to produce excess hydroxonium ions H₃O⁺ in an aqueous solution.

For example:

               HCl + H₂O → H₃O⁺ + Cl⁻

HCl is classified as a strong acid due to its complete ionization when in solutions.

3 0
3 years ago
How does the magnetic field surrounding earth benefit humankind
Xelga [282]
C, it prevents the Earth from ultraviolet radiation and other harmful substances from space
5 0
3 years ago
Read 2 more answers
Which of the following compounds is always part of an aqueous solution?
jolli1 [7]
A.water.
An aqueous solution is a solution in water.
Hope this helped :)
5 0
3 years ago
Read 2 more answers
Sắp xếp các hợp chất: HF, HI, HBr, HCl theo chiều giảm dần tính axit.
mixer [17]
I don’t know what to answer
6 0
2 years ago
Other questions:
  • Spacing is often important in the name of a compound. For example, carboxylic acids are named using the parent carbon chain (wit
    7·2 answers
  • How many moles of chlorine gas is contained in 4.81x10^24 molecules
    8·1 answer
  • Isotopes of the same element have different numbers of ________.
    9·2 answers
  • Choose the pure substance from the list below. choose the pure substance from the list below. lemonade wine air juice salt
    5·1 answer
  • Conduction transfers thermal energy by____.
    13·2 answers
  • The amount of inertia an object has depends on its speed true or false
    9·2 answers
  • Hi!! can someone pls help me with this question? ASAP PLS!
    13·2 answers
  • Do oxygen atoms become more stable or less stable when oxygen forms compounds? Explain. Pls help
    10·1 answer
  • ________ is the force that keeps planets in orbit around the sun
    6·2 answers
  • What tiles should I put in the box?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!