A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut
ion containing 0.75 grams of copper (II) chloride. A single replacement reaction takes place. Which statement explains the maximum amount of copper that the chemist can extract using this reaction? Unbalanced equation: CuCl2 + Al → AlCl3 + Cu Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant Approximately 1.8 grams, because copper (II) chloride acts as a limiting reactant Approximately 0.36 grams, because aluminum acts as a limiting reactant Approximately 1.8 grams, because aluminum acts as a limiting reactant
So would you say that less than 5.3 g of copper II is formed and some aluminum is left in the reaction mixture? Aluminium is the limiting reactant meaning all of it is consumed in the reaction. Only copper chloride is in excess and hence some of it remain in solution.
Hello mayaredalen. I do believe the exact corrected balanced equation will be that of 2 H2+2 Cl2=> 4 HCl. I'm really sorry if I gave you any wrong information. It's best to make sure before importing such a balance equation to your assignment.
