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KIM [24]
3 years ago
14

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut

ion containing 0.75 grams of copper (II) chloride. A single replacement reaction takes place. Which statement explains the maximum amount of copper that the chemist can extract using this reaction? Unbalanced equation: CuCl2 + Al → AlCl3 + Cu Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant Approximately 1.8 grams, because copper (II) chloride acts as a limiting reactant Approximately 0.36 grams, because aluminum acts as a limiting reactant Approximately 1.8 grams, because aluminum acts as a limiting reactant
Chemistry
2 answers:
Y_Kistochka [10]3 years ago
8 0
So would you say that less than 5.3 g of copper II is formed and some aluminum is left in the reaction mixture? Aluminium is the limiting reactant meaning all of it is consumed in the reaction. Only copper chloride is in excess and hence some of it remain in solution.
Allisa [31]3 years ago
4 0
I really need help on this
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How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
2 years ago
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6 0
2 years ago
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<u>Answer:</u> The correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.  

The balanced molecular equation is:

Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)

The complete ionic equation follows:

Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

Hence, the correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

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False, where does the chlorine come from light anyway???????
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