Which of the following has more atoms 3.14 g Cu or 1.10 g of H? Explain

1 answer:

8 0

63.5 gm cu contain 6.02*10^23 molec
1 gm cu contain 6.02*10^23/63.5
3.14 gm contain 6.02*10^23*3.14/63.5

similary in case of H2
1.10*6.02*10^23/2

then you can compare the result

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At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5

Annette [7]

Answer:

4600s

Explanation:

$2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}$

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

$-\frac{d[B]}{dt}=k[B] - - - -\frac{d[B]}{[B]}=k*dt$

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.

$-\frac{d[P(B)]}{P(B)}=k*dt$

$-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt$

Integrating we get:

$\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt$

$-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})$

Clearing for t2:

$\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}$

$ln[P(N_{2}O_{5})]=ln(650)=6.4769$

$ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333$

$t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s$

4 0

3 years ago

Can you determine the molecular formula of a substance from its percent composition

Natalka [10]

The percent composition gives you only the empirical formula.
To get the molecular formula, you must either know the molecular mass or do an experiment to find it.

8 0

3 years ago

.22

Alja [10]

Answer:its b

Explanation:

7 0

3 years ago

Read 2 more answers

ANSWER IN YOUR OWN WORDS! How does the pH of an acid compare with the pH of a neutral solution?

Lady bird [3.3K]

Answer: