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ValentinkaMS [17]
3 years ago
6

Which of the following has more atoms 3.14 g Cu or 1.10 g of H? Explain

Chemistry
1 answer:
ziro4ka [17]3 years ago
8 0
63.5 gm cu contain 6.02*10^23 molec
1 gm cu contain 6.02*10^23/63.5
3.14 gm contain 6.02*10^23*3.14/63.5

similary in case of H2
1.10*6.02*10^23/2

then you can compare the result
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Organic compounds that are synthesized by human cells
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Organic compounds essential to human functioning include carbohydrates, lipids, proteins, and nucleotides. These compounds are said to be organic because they contain both carbon and hydrogen.
4 0
3 years ago
51. The radius of gold is 144 pm and the density is 19.32 g/cm3. Does elemental gold have a face-centered cubic structure or a b
Serjik [45]

Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

Its density = 19.32 g/cm³

Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

a = \sqrt{8} r

a = \sqrt{8} \times 144 pm

a = 407 pm

In a unit cell, Volume (V) = a³

V = (407 pm)³

V = 6.74 × 10⁷ pm³

V = 6.74 × 10⁻²³ cm³

Recall that:

Net no. of an atom in an FCC unit cell = 4

Thus;

density = \dfrac{mass}{volume}

density = \dfrac{ 4 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{6.74 \times 10^{-23} \ cm^3}

density d = 19.41 g/cm³

Similarly; For a  body-centered cubic structure

r = \dfrac{\sqrt{3}}{4}a

where;

r = 144

144 = \dfrac{\sqrt{3}}{4}a

a = \dfrac{144 \times 4}{\sqrt{3}}

a = 332.56 pm

In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

V  3.68 × 10⁻²³   cm³

Recall that:

Net no. of atoms in BCC cell = 2

∴

density = \dfrac{mass}{volume}

density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}

density =17.78 g/cm³

From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.

This makes the elemental gold to have a Face-centered cubic structure.

3 0
3 years ago
For the formula shown, how many sulfur atoms are represented?
Tatiana [17]

Answer:

i also need the is question help!!!

Explanation:

8 0
2 years ago
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Over [174]

Explanation:

Non-metals are the species that are electron deficient and they are able to accept one or more electrons from a donor atom in order to complete their octet.

For  example, carbon (C), nitrogen (N), chlorine, (Cl), phosphorus (P) etc are all non-metals.

Metals are the species that contain more number of electrons in their valence shell and in order to attain stability they easily lose an electron.

For example, sodium (Na), lithium (Li), Beryllium (Be), Magnesium (Mg) etc are all metals.

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5 0
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Please help,<br> How could you tell a Ca(NO3)2 solution from a Zn(NO3)2 solution?
tamaranim1 [39]

Answer:

you better give me brainliest

Explanation:

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