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STatiana [176]
3 years ago
7

Tengo un volumen desconocido de gas mantenido a una temperatura de 115 K en un recipiente con una presión de 60.0 atm. Si al aum

entar la temperatura a 225 K y disminuir la presión a 30.0 atm hace que el volumen del gas sea de 29.0 litros, ¿con cuántos litros de gas comencé?
Chemistry
1 answer:
Delvig [45]3 years ago
6 0

Answer:

be nice bother high school bo

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What are the 7 methods of separating mixtures?​
Gennadij [26K]

Methods Of Separating Mixtures

Handpicking.

Threshing.

Winnowing.

Sieving.

Evaporation.

Distillation.

Filtration or Sedimentation.

Separating Funnel.

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3 years ago
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Consider the combustion of glucose: c6h12o6(s) + 6 o2(g) ←→ 6 co2(g) + 6 h2o(g) ∆h = −2, 800 kj/mol which condition i) adding mo
Verizon [17]
The answer is iii) decreasing the pressure of the system. When the pressure is decreased, the equilibrium will shift to the right because it has 12 moles of gas which is greater than the number of moles of gas on the left side, which is 6 moles. Equilibrium shifting to the side that exerts greater pressure is favored to offset the decrease in pressure.
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3 years ago
Calcium reacts with Hydrochloric acid to produce Calcium chloride and
hammer [34]

Answer:

Mass = 2.77 g

Explanation:

Given data:

Mass of HCl = 2 g

Mass of CaCl₂ produced = ?

Solution:

Chemical equation:

2HCl + Ca    →     CaCl₂ + H₂

Number of moles of HCl:

Number of moles = mass / molar mass

Number of moles = 2 g/ 36.5 g/mol

Number of moles = 0.05 mol

now we will compare the moles of HCl with CaCl₂.

                   HCl       :         CaCl₂

                     2         :          1

                   0.05     :       1/2×0.05 = 0.025 mol

Mass of CaCl₂:

Mass = number of moles × molar mass

Mass = 0.025 mol × 110.98 g/mol

Mass = 2.77 g

8 0
3 years ago
What can cause a mutation when the cell copies its DNA?
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Answer:

exposure to radiation i think

Explanation:

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Does this equation support the law of conservation of mass?
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this equation does support the law of conservation of mass.

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