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3 years ago

How is the behavior of electrons in an ionic bond different from the behavior of electrons in a covalent bond?

Chemistry

2 answers:

Valentin [98]3 years ago

8 0

Answer:

The correct answer is "Electrons are transferred in an ionic bond"

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

In conclusion, chemical bonds are made so that atoms can have their entire outer layer, and thus have a stable electronic configuration. In the ionic bond, when the metallic atom has only one electron in its outer layer and the non-metallic one needs an electron to complete its layer; The metallic atom seats its electron to the non-metallic one. In the same way, the electron is shared in the covalent bond in order to achieve equilibrium.

Then, the main differences between the two bonds are that the ionic bond occurs between two different atoms (metallic and non-metallic), while the covalent bond occurs between two equal atoms (non-metallic). And in the covalent bond there is an electron compartment, while in the ionic bond there is an electron transfer.

So, the correct answer is "Electrons are transferred in an ionic bond"

xeze [42]3 years ago

7 0

Answer:

In ionic bonds, an atom donates an electron to another atom to stabilize it. The electron spends more time with the bonded atom.

In covalent bonds, atoms bond by sharing electrons equally.

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Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.

exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

= (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

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3 years ago

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What is the correct ionic formula when mg2+ and p3− react?

Mumz [18]

Answer: Ionic formula will be $Mg_3P_2$ .

Explanation: $Mg^{2+}$ and $P^{3-}$ ions will form a ionic compound. Ionic compounds have both metals and non-metals.

Here $Mg^{2+}$ is a metal and $P^{3-}$ is a non-metal.

The net charge on any compound must be 0.

So we need 2 phosphate ions to balance the charge on $Mg^{2+}$ ions. Similarly we need 3 Magnesium ions to balance the charge on $P^{3-}$ ions.

Criss-crossing the charges, we will get the formula as $Mg_3P_2$

Criss-crossing is shown in the image below.

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Where can you find the information needed to change grams of a substance to moles?

vlada-n [284]

Oxidation numbers is the right answer

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Which planet formed near the sub where the solar system l’s temperatures were very high

Harrizon [31]

Answer:

Mars

Explanation:

Terrestrial or inner planets like Mars and Venus were formed near the Sun where the solar system's temperatures were very high.

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A 46.9 gram sample of a substance has a volume of about 3.5 centimeters3. It is solid at a room temperature of 23ºC. Out of the

horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution : Given,

Mass of given substance (m) = 46.9 g

Volume of given substance (V) = 3.5 $Cm^{3}$

First, find the Density of given substance.

Formula used :

$Density=\frac{\text{Mass of given substance}}{\text{Voume of given substance}}$

Now,put all the values in this formula, we get

$Density=\frac{46.9 g}{3.5 Cm^{3} }$ = 13.4 g/ $Cm^{3}$

So, we conclude that the density of given substance (13.4 g/ $Cm^{3}$ ) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/ $Cm^{3}$ respectively).

According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.

Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.

So, Hafnium is the most likely element which is the identity of the given substance.

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