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Dafna11 [192]
3 years ago
10

-what meal do you eat after doing those exercises?

Physics
2 answers:
TiliK225 [7]3 years ago
6 0
I eat dicks and and I also masturbate
o-na [289]3 years ago
6 0

Answer:

this is my answer in the first question...

Fuel your body for everyday performance

To help your muscles recover and to replace their glycogen stores, eat a meal that contains both carbohydrates and protein within two hours of your exercise session if possible. Good post-workout food choices include: Yogurt and fruit. Peanut butter sandwich

my family motivated me to achieve it because they support me and my self also because if i did not do my best i would not achieve it

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A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction par
zloy xaker [14]

Answer:

10ms

Explanation:

The bird must travel the length of the train (150m), with a combined speed of 15m/s this means it will take 10s to cross an accumulated 150ms.

3 0
4 years ago
Read 2 more answers
Calculate the density of each ball. Use the formula
Paraphin [41]

Answer:

⇒ 0.07 g/cm3  

⇒ 1.15 g/cm3

Explanation:

3 0
3 years ago
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10 The magnitude J of the current density in a certain lab wire with a circular cross section of radius R = 2.00 mm is given by
rewona [7]

Answer:

I = 0.002593 A = 2.593 mA

Explanation:

Current density = J = (3.00 × 10⁸)r² = Br²

B = (3.00 × 10⁸) (for ease of calculations)

The current through outer section is given by

I = ∫ J dA

The elemental Area for the wire,

dA = 2πr dr

I = ∫ Br² (2πr dr)

I = ∫ 2Bπ r³ dr

I = 2Bπ ∫ r³ dr

I = 2Bπ [r⁴/4] (evaluating this integral from r = 0.900R to r = R]

I = (Bπ/2) [R⁴ - (0.9R)⁴]

I = (Bπ/2) [R⁴ - 0.6561R⁴]

I = (Bπ/2) (0.3439R⁴)

I = (Bπ) (0.17195R⁴)

Recall B = (3.00 × 10⁸)

R = 2.00 mm = 0.002 m

I = (3.00 × 10⁸ × π) [0.17195 × (0.002⁴)]

I = 0.0025929449 A = 0.002593 A = 2.593 mA

Hope this Helps!!!

4 0
3 years ago
Q1) An average force of 50.0 N is exerted on a 4.0-kg cart for 2.0 seconds.
lozanna [386]
<h3>a. The impulse</h3>

The impulse is 100.0 Ns

The impulse I = Ft where

  • F =average force = 50.0 N and
  • t = time = 2.0 s

Substituting these values into the equation, we have

I = Ft

I = 50.0 N × 2.0 s

I = 100.0 Ns

The impulse is 100.0 Ns

<h3>b. Change in momentum</h3>

The change in momentum is 100 kgm/s

Since change in momentum Δp = I where I = impulse.

Since I = 100.0 Ns,

Substituting this into the equation, we have

Δp = I

= 100.0 Ns

= 100 kgm/s

The change in momentum is 100 kgm/s

<h3>c. Mass's change in velocity</h3>

The change in velocity is 25.0 m/s

Since change in momentum Δp = mΔv where

  • m = mass = 4.0 kg and
  • Δv = change in velocity.

Making Δv subject of the formula, we have

Δv = Δp/m

Substituting the values of the variables into the equation, we have

Δv = Δp/m

Δv = 100.0 kgm/s/4.0 kg

Δv = 25.0 m/s

The change in velocity is 25.0 m/s

Learn more about impulse here:

brainly.com/question/25700778

3 0
3 years ago
Gina is driving her car to work, but she’s stopped at a red light. When the light turns green, she presses the gas pedal and acc
Alex777 [14]
The net force of the car is greater than zero in the horizontal direction. If it were not greater thn zero, then the vehicle would remain stationary.
8 0
3 years ago
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