Evaporation from the rivers, seas and so on,
and transpiration from the plants.
Answer:
0.302L
Explanation:
<em>...97.1mL of 1.21m M aqueous magnesium fluoride solution</em>
<em />
In this problem the chemist is disolving a solution from 1.21mM = 1.21x10⁻³M, to 389μM = 389x10⁻⁶M. That means the solution must be diluted:
1.21x10⁻³M / 389x10⁻⁶M = 3.11 times
As the initial volume of the original concentration is 97.1mL, the final volume must be:
97.1mL * 3.11 = 302.0mL =
0.302L
Answer:
See the explanation and examples below, please.
Explanation:
To calculate the molar mass of a substance you must have the atomic weights of each component:
Example NaCl ionic compound (sodium chloride, known as table salt)
Molar mass NaCl = Atomic weight Na + Atomic weight Cl = 22, 98 gr + 35, 45gr = 58.35 grams / mol
Example covalent compound HCl (hydrochloric acid) = Atomic weight H + Atomic weight Cl = 1, 004gr + 35, 45 gr = 36, 45 grams / mol
In the case of having compound H20 (water), it is calculated:
Molar mass NaCl = 2 x (Atomic weight H) + Atomic weight 0 (the atomic weight of 1 mol of Hydrogen is multiplied by 2)
Answer:Four types of vaccines are currently available: Live virus vaccines use the weakened (attenuated) form of the virus. The measles, mumps, and rubella (MMR) vaccine and the varicella (chickenpox) vaccine are examples
Explanation:
The given data is as follows.
T = 298 K, 
= -5645 kJ/mol
= -5798 kJ/mol
Relation between 
and 
are as follows.
= 
-5798 kJ/mol = -5645 kJ/mol - 
-153 kJ/mol = -
= 0.513 kJ/mol K
Now, temperature is 
= (37 + 273) K = 310 K
Since, =
= 
= (-5645 kJ/mol - 159.03 kJ/mol)
= -5804.03 kJ/mol
As, change in Gibb's free energy = maximum non-expansion work
= -5804.03 kJ/mol - (-5798 kJ/mol)
= -6.03 kJ/mol
Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.
