Answer:
3.39g of MgBr
Explanation:
Reaction between magnesium and bromine
Mg + Br₂ → MgBr
Mass of MgBr = ?
1g of Mg + 5.0g of Br₂
6g of Mg and Br₂
Molar mass of Mg = 24g/mol
Molar mass of Br = 80g/mol
Number of moles = mass / molar mass
Mass = number of moles * molarmass
Mass of Mg = 1 * 24 = 24g
Mass of Br₂ = 1 * (2*80) = 160g (diatomic molecule)
Molarmass of MgBr = (24 + 80) = 104g/mol
Mass of MgBr = 1 * 104 = 104g/mol
24g of Mg + 160g of Br₂ = 104g of MgBr
184g of (mg and Br) = 104g of mgBr
6g of (mg and Br) = y g of MgBr
y = (6 * 104) / 184
y = 3.39g of MgBr
1. Heart
2. Circulatory system
3. The circulatory system delivers oxygen and nutrients to cells and take away water .
4. Your heart is a muscle and it’s job is to pump blood throughout your circulatory system.
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Answer:
0.287 mole of PCl5.
Explanation:
We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:
Molar mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 = 51g
Number of mole of Cl2 =..?
Mole = Mass /Molar Mass
Number of mole of Cl2 = 51/71 = 0.718 mole
Next, we shall write the balanced equation for the reaction. This is given below:
P4 + 10Cl2 → 4PCl5
Finally, we determine the number of mole of PCl5 produced from the reaction as follow:
From the balanced equation above,
10 moles of Cl2 reacted to produce 4 moles of PCl5.
Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.
Therefore, 0.287 mole of PCl5 is produced from the reaction.
Answer:
Elliptical galaxies are one of the three types of galaxies. They have a rounded shape of an ellipse, like a stretched-out circle. They lack the swirling arms that are a main feature of spiral galaxies.
Answer:
fraction of vacancies for this metal FV = 1.918*10⁻⁴
Explanation:
Given:
The number of vacancies per unit volume => ( Nv = 1*10²⁵ m⁻³ )
But we know that Avogrado's constant NA = 6.022*10²³ atoms/mol
Density of the material is given in g/cm3 we need to convert it to g/m³
Density of material ( p ) in g/m³ :
To convert we know that
1 g/cm³ = 1000000 g/m³ then
7.40 * ( 1000000 ) = 7.40*10⁶ g/m³
So, Density of material ( p ) in g/m³ = 7.40*10⁶ g/m³
Given Atomic mass = 85.5 g/mol
To Calculate the number of atomic sites per unit volume , we will use the below formula by substituting those values above
N = NA * p / A
N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5
N = 4.45*10³⁰ / 85.5
N = 5.212*10²⁸ atoms/m³
We can now Calculate the fraction of vacancies using the formula below;
Fv = Nv / N
Fv = 1*10²⁵ / 5.212*10²⁸
fraction of vacancies for this metal at 600c.= 1.918*10⁻⁴
