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Alchen [17]
3 years ago
5

The amount of water (density 1.00 g mL-1) in grams that must be added to 26.2 g of

Chemistry
1 answer:
Damm [24]3 years ago
5 0

Answer:

1720.8g water are necessaries

Explanation:

Mass percent is defined as the mass of solute (In this case, MgCl2) in 100g of solution (Mass MgCl2 + Mass water). To solve this question we must find the mass of solution that we need to produce th 1.5% by mass solution. Thus, we can find the mass of water that we need as follows:

<em>Mass solution:</em>

26.2g MgCl2 * (100g Solution / 1.5g MgCl2) = 1747g solution

<em>Mass water:</em>

1747g solution - 26.2g MgCl2 = 1720.8g water are necessaries

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abruzzese [7]

The answer is RuBP.

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Calvin Cycle consists of three stages:
1. fixation: the enzyme RuBisCO incorporates (fixes) carbon-dioxide into 3-PGA.
2. reduction: 3-PGA is reduced using NADPH as electron supply.
<span><u>3. regeneration: RuBP is regenerated and starts the cycle again.</u></span></span>

8 0
3 years ago
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Whats the balanced equation for sodium hydroxide + ammonium sulphate=sodium sulphate + amonia + h2o​
Nady [450]

Answer:

2NaOH + (NH4) 2SO4 = Na2SO4(s) + 2NH3(g) + 2H2O(l)

Two moles of sodium hydroxide reacts with 1 Mike of ammonium sulphate to give 1 mole of Sodium sulphate, 2 moles of ammonia gas and 2 moles of water

Explanation:

7 0
3 years ago
What is the mass of solute dissolved in 50,0 g of 12.5% saline solution? A) 7.148 B) 6.258 C) 43.88 D) 4.00 g
Marizza181 [45]

Answer:

6.25 grams is the mass of solute dissolved.

Explanation:

w/w % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

Mass of the solution = 50.0 g

Mass of the solvent = x

w/w % = 12.5%

12.5\%=\frac{x}{50.0 g}\times 100

x = 6.25 g

6.25 grams is the mass of solute dissolved.

6 0
3 years ago
Please answer truthfully:))​
makvit [3.9K]

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Fast, Direction, Time

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4 0
3 years ago
What<br>was the initial volume of the hydrogen in cm3?​
svetlana [45]

Answer:

255.51cm3

Explanation:

Data obtained from the question include:

V1 (initial volume) =?

T1 (initial temperature) = 50°C = 50 + 273 = 323K

T2 (final temperature) = - 5°C = - 5 + 237 = 268K

V2 (final volume) = 212cm3

Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:

V1/T1 = V2/T2

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Cross multiply to express in linear form

V1 x 268 = 323 x 212

Divide both side by 268

V1 = (323 x 212)/268

V1 = 255.51cm3

Therefore, the initial volume of the gas is 255.51cm3

5 0
3 years ago
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