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Alchen [17]
3 years ago
5

The amount of water (density 1.00 g mL-1) in grams that must be added to 26.2 g of

Chemistry
1 answer:
Damm [24]3 years ago
5 0

Answer:

1720.8g water are necessaries

Explanation:

Mass percent is defined as the mass of solute (In this case, MgCl2) in 100g of solution (Mass MgCl2 + Mass water). To solve this question we must find the mass of solution that we need to produce th 1.5% by mass solution. Thus, we can find the mass of water that we need as follows:

<em>Mass solution:</em>

26.2g MgCl2 * (100g Solution / 1.5g MgCl2) = 1747g solution

<em>Mass water:</em>

1747g solution - 26.2g MgCl2 = 1720.8g water are necessaries

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If all the reactors are used, the pressure inside the flask will most likely increase to 4 atm.

<h3>What is atmospheric pressure?</h3>

Atmospheric pressure is a force per unit area exerted by the air in the atmosphere on the Earth's surface. The value of atmospheric pressure above sea level is 1013.25 hPa.

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According to the above, if all the reactors are used at atmospheric pressure, it will most likely increase.

Note: This question is incomplete because some information is missing. However I can answer it based on my prior knowledge.

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Assume that all of this fossil fuel is in the form of octane (C8H18) and calculate how much CO2 in kilograms is produced by worl
AnnZ [28]

The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately 9.50\times 10^{12} kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: 29\times 10^{12}kg

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles

According to stoichiometry :

As 2 moles of octane give = 16 moles of CO_2

Thus 0.083\times 10^{15}moles of octane give =\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg

Thus 29\times 10^{12}kg of CO_2 is produced by world fossil fuel combustion per year.

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Explanation:

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