<span>For this reaction, oxidation number of Carbon in
CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this
means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While
oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced.
The reducing agent is the one which provides electrons by oxidizing itself so
in this case; CO is the reducing agent while the C in CO oxidized to produce
electrons. </span><span>I
am hoping that this answer has satisfied your query about and it will be able
to help you, and if you’d like, feel free to ask another question.</span>
The equation that shows the formation of chromium (ii) ion from neutral chromium atom is as follow
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
Answer:
[2 ]Na+[2 ]H2O -> [ 2] NaOH + [1]H2
Answer:
First of all, the equation is typed wrong so it can easily be misinterpreted
Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)
CH4 + 2O2 -----> CO2 + 2H2O
And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.
The answer is Rubidium (Rb)
