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telo118 [61]
3 years ago
10

A small pebble and a large boulder start at the same height and begin rolling down the side of a mountain.Which object would hav

e less kinetic energy as it crashes on the road at the bottom of the mountain?
Chemistry
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

The large boulder

Explanation:

An object’s kinetic energy depends on:

● the object’s mass and

● the object’s speed

Let us remember that the magnitude of acceleration due to gravity on the both objects is exactly the same.

However, the mass of the objects are different. Mass is a measure of the inertia (resistance to motion) of a body. The greater the mass, the greater the inertial. The boulder has a greater mass and hence a greater inertia (more resistance to motion).

Therefore, the boulder will have less kinetic energy

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A student prepares a mixture of sugar and coffee. The sugar seems to disappear as it mixes with the coffee.
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Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0
3 years ago
Identify the effect of increasing acidity on the solubility of the given compounds. Drag the appropriate items to their respecti
PIT_PIT [208]

Answer:

Ca3(PO4)2- Increase in solubility

Barium hydroxide- increase in solubility

Magnesium carbonate- increase in solubility

Copper II sulphide- increase solubility

Lead II bromide- increase solubility

CuI - increase solubility

Explanation:

Calcium phosphate solubility is pH dependent. At lower pH, calcium phosphate is more soluble in water while at pH above 8.5, the solubility of calcium phosphate decreases markedly.

For Barium hydroxide and magnesium carbonate,decreasing the pH will increase the solubility of the compound.

For copper II sulphide,decreasing the pH will lead to a greater solubility. Also, lead II bromide is ordinarily insoluble in water but it's solubility increases with decreasing pH.

CuI is insoluble in water but soluble in dilute hydrochloric acid.

6 0
3 years ago
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