They can both be converted to each other. Hopefully this helps! :)<span />
Answer : The enthalpy of the reaction is, -2552 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given enthalpy of reaction is,

The intermediate balanced chemical reactions are:
(1)

(2)

(3)

(4)

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :
(when we are reversing the reaction then the sign of the enthalpy change will be change.)
The expression for enthalpy of the reaction will be,



Therefore, the enthalpy of the reaction is, -2552 kJ/mole
Answer:
Ca3(PO4)2- Increase in solubility
Barium hydroxide- increase in solubility
Magnesium carbonate- increase in solubility
Copper II sulphide- increase solubility
Lead II bromide- increase solubility
CuI - increase solubility
Explanation:
Calcium phosphate solubility is pH dependent. At lower pH, calcium phosphate is more soluble in water while at pH above 8.5, the solubility of calcium phosphate decreases markedly.
For Barium hydroxide and magnesium carbonate,decreasing the pH will increase the solubility of the compound.
For copper II sulphide,decreasing the pH will lead to a greater solubility. Also, lead II bromide is ordinarily insoluble in water but it's solubility increases with decreasing pH.
CuI is insoluble in water but soluble in dilute hydrochloric acid.