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Murrr4er [49]
3 years ago
12

A rock that is made of coarse-grained particles arranged into bands is found. What type of rock is it?

Physics
2 answers:
aleksklad [387]3 years ago
4 0
The answer you are looking for is Gneiss my dude. 
Firlakuza [10]3 years ago
4 0

gneiss, a metamorphic rock

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I dont get why its c i dont under the graph for the vertical component in option c
jek_recluse [69]
The vertical component grows at an increasing rate because
gravity is ACCELERATING the object vertically.  So its speed
keeps growing.  Speed is the slope of the displacement graph.
7 0
3 years ago
What important milestone occurred as a result of the Soviets' use of the R-7
AleksAgata [21]

Answer:

d

Explanation:

4 0
2 years ago
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Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after
adoni [48]

Answer: v = 1.19 * 10^{6} m/s

Explanation: q = magnitude of electronic charge = 1.609 * 10^{-19} c

mass of an electronic charge = 9.10 * 10^{-31} kg

V= potential difference = 4V

v = velocity of electron

by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.

kinetic energy = \frac{mv^{2} }{2},  potential energy = qV

hence, \frac{mv^{2} }{2} = qV

\frac{9.10 *10^{-31} * v^{2}  }{2} = 1.609 * 10^{-16} * 4\\\\\\\\9.10*10^{-31}  * v^{2} = 2 * 1.609 *10^{-16} * 4\\\\\\9.10 *10^{-31} * v^{2} = 1.287 *10^{-15} \\\\v^{2} = \frac{1.287 *10^{-15} }{9.10 *10^{31} } \\\\v^{2} = 1.414*10^{15} \\\\v = \sqrt{1.414*10^{15} } \\\\v = 1.19 * 10^{6} m/s

7 0
2 years ago
What happens if you go through a black hole ?
devlian [24]

Explanation:

The intense gravity of the black hole would pull you apart, separating your bones and muscles.

7 0
3 years ago
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Which of the following wavelengths will produce standing waves on a string that is 3.5 m long?
denpristay [2]

In a string of length L, the wavelength of the n-th harmonic of the standing wave produced in the string is given by:

\lambda=\frac{2}{n} L


The length of the string in this problem is L=3.5 m, therefore the wavelength of the 1st harmonic of the standing wave is:

\lambda=\frac{2}{1} \cdot 3.5 m=7.0 m


The wavelength of the 2nd harmonic is:

\lambda=\frac{2}{2} \cdot 3.5 m=3.5 m


The wavelength of the 4th harmonic is:

\lambda=\frac{2}{4} \cdot 3.5 m=1.75 m


It is not possible to find any integer n such that \lambda=5 m, therefore the correct options are A, B and D.

3 0
3 years ago
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