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Murrr4er [49]
3 years ago
12

A rock that is made of coarse-grained particles arranged into bands is found. What type of rock is it?

Physics
2 answers:
aleksklad [387]3 years ago
4 0
The answer you are looking for is Gneiss my dude. 
Firlakuza [10]3 years ago
4 0

gneiss, a metamorphic rock

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The magnetic field 0.02 m from a wire is 0.1 t. what is the magnitude of the magnetic field 0.01 m from the same wire?
juin [17]

Answer:

0.2 T

Explanation:

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A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. The ra
Pavlova-9 [17]

The minimum speed of the water must be 3.4 m/s

Explanation:

There are two forces acting on the water in the pail when it is at the top of its circular motion:

  • The force of gravity, mg, acting downward (where m is the mass of the water and g the acceleration of gravity)
  • The normal reaction, N also acting downward

Since the water is in circular motion, the net force must be equal to the centripetal force, so:

N+mg=m\frac{v^2}{r}

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v is the speed of the pail

r = 1.2 m is the radius of the circle

The water starts to spill out when the normal reaction of the pail becomes zero:

N = 0

When this occurs, the equation becomes:

mg=m\frac{v^2}{r}\\v=\sqrt{gr}

And substitutin the values of g and r, we find the minimum speed that the water must have in order not to spill out:

v=\sqrt{(9.8)(1.2)}=3.4 m/s

Learn more about circular motion:

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6 0
3 years ago
A boat with a weight of 547 newtons is floating in a harbor. What is the buoyant force on the boat?
Veronika [31]

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a

Explanation:

its correct

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3 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
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Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

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3 years ago
Did i get any of these answers right if not what do i have to change
gregori [183]

Answer:

You got them right

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