Answer:
Computer programming for three dimensional designs
Explanation:
- Doll is not a 2D creation . it's a 3D creation
- So on creating the design on 3D scale it's more effective to determine what can be added more.
Answer:
a)
, b)
, c) ![T = 200.829\,^{\textdegree}F](https://tex.z-dn.net/?f=T%20%3D%20200.829%5C%2C%5E%7B%5Ctextdegree%7DF)
Explanation:
a) The tank can be modelled by the Principle of Mass Conservation:
![\dot m_{1} + \dot m_{2} - \dot m_{3} = 0](https://tex.z-dn.net/?f=%5Cdot%20m_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D%20-%20%5Cdot%20m_%7B3%7D%20%3D%200)
The mass flow rate exiting the tank is:
![\dot m_{3} = \dot m_{1} + \dot m_{2}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20%5Cdot%20m_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D)
![\dot m_{3} = 125\,\frac{lbm}{s} + 10\,\frac{lbm}{s}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20125%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%2B%2010%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D)
![\dot m_{3} = 135\,\frac{lbm}{s}](https://tex.z-dn.net/?f=%5Cdot%20m_%7B3%7D%20%3D%20135%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D)
b) An expression for the specific enthalpy at outlet is derived from the First Law of Thermodynamics:
![\dot m_{1}\cdot h_{1} + \dot m_{2} \cdot h_{2} - \dot m_{3}\cdot h_{3} = 0](https://tex.z-dn.net/?f=%5Cdot%20m_%7B1%7D%5Ccdot%20h_%7B1%7D%20%2B%20%5Cdot%20m_%7B2%7D%20%5Ccdot%20h_%7B2%7D%20-%20%5Cdot%20m_%7B3%7D%5Ccdot%20h_%7B3%7D%20%3D%200)
![h_{3} = \frac{\dot m_{1}\cdot h_{1}+\dot m_{2}\cdot h_{2}}{\dot m_{3}}](https://tex.z-dn.net/?f=h_%7B3%7D%20%3D%20%5Cfrac%7B%5Cdot%20m_%7B1%7D%5Ccdot%20h_%7B1%7D%2B%5Cdot%20m_%7B2%7D%5Ccdot%20h_%7B2%7D%7D%7B%5Cdot%20m_%7B3%7D%7D)
Properties of water are obtained from tables:
![h_{1}=180.16\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B1%7D%3D180.16%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
![h_{2}=28.08\,\frac{BTU}{lbm} + \left(0.01604\,\frac{ft^{3}}{lbm}\right)\cdot (14.7\,psia-0.25638\,psia)](https://tex.z-dn.net/?f=h_%7B2%7D%3D28.08%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%2B%20%5Cleft%280.01604%5C%2C%5Cfrac%7Bft%5E%7B3%7D%7D%7Blbm%7D%5Cright%29%5Ccdot%20%2814.7%5C%2Cpsia-0.25638%5C%2Cpsia%29)
![h_{2}=29.032\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B2%7D%3D29.032%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
The specific enthalpy at outlet is:
![h_{3}=\frac{(125\,\frac{lbm}{s} )\cdot (180.16\,\frac{BTU}{lbm} )+(10\,\frac{lbm}{s} )\cdot (29.032\,\frac{BTU}{lbm} )}{135\,\frac{lbm}{s} }](https://tex.z-dn.net/?f=h_%7B3%7D%3D%5Cfrac%7B%28125%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%29%5Ccdot%20%28180.16%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%29%2B%2810%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%29%5Ccdot%20%2829.032%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D%20%29%7D%7B135%5C%2C%5Cfrac%7Blbm%7D%7Bs%7D%20%7D)
![h_{3}=168.965\,\frac{BTU}{lbm}](https://tex.z-dn.net/?f=h_%7B3%7D%3D168.965%5C%2C%5Cfrac%7BBTU%7D%7Blbm%7D)
c) After a quick interpolation from data availables on water tables, the final temperature is:
![T = 200.829\,^{\textdegree}F](https://tex.z-dn.net/?f=T%20%3D%20200.829%5C%2C%5E%7B%5Ctextdegree%7DF)
Answer:
(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift
Explanation:
When a fluid flows around the surface of an object, it exerts a force on it. This force has two components, namely lift and drag.
The component of this force that is perpendicular (normal) to the freestream velocity is known as lift, while the component of this force that is parallel or in the direction of the fluid freestream flow is known as drag.
Lift is as a result of pressure differences, while drag results from forces due to pressure distributions over the object surface, and forces due to skin friction or viscous force.
Thus, drag results from the combination of pressure and viscous forces while lift results only from the<em> pressure differences</em> (not pressure forces as was used in option D).
The only correct option left is "A"
(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift
Answer:
Explanation:
For automobile emission, a uniform standard is preferred, because no unnecessary advantage is given by it to any company that is located in particular states where the regional standards are less severe.
Since pollution has its impact across the states and in the whole of the USA, then there should be uniform standards across all the states. It will also invalidate the impact of regional standards as a factor in the selection of plant locations for the automobile company. It means that a state offering less valid emission standards, will attract more companies to herself and it will be against the other states who care more about the natural environment. It can make more states to opt for the permissive emission standards, that will be more harmful to the USA as a country, than the good. So, a uniform standard is preferred to eliminate it as a factor in plant location decisions.
Yes, uniform standards are beneficial to everyone, because it will bring effective control upon the pollution level because there will be no state where the culprit firm can hide. Besides, it is more effective as efforts done towards environment conservation.
Measure the longest circuit and add 50% for fittings and terminal units.