Answer:
sorry I didn't get it
Explanation:
could you please circle the question that I can identify the question and tell you tge answer.
I am an expert in maths. I am not praising myself becoz I know self praise is no praise. But I said I am an expert becoz I want to tell you people that if I an expert cannot identify the answer so nobody can identify.
Answer:
A ball bearing has been selected with the bore size specified in the catalog as 35.000 mm to 35.020 mm. Specify.... ... has been selected with the bore size specified in the catalog as 35.000 mm to 35.020 mm. Specify appropriate minimum and maximum shaft diameters to provide a locational interference fit.
Explanation:
Answer:
61.5 °C
Explanation:
The resistance of the relay coil at 15 °C is R = V/I = 6/0.12 = 50 ohms. In order for the coil current to remain above 0.10 A, the resistance must remain below R = 6/0.10 = 60 ohms.
At some temperature difference ΔT from 15 °C, the resistance of the coil will be ...
R = R0(1 +α·ΔT)
where R0 is the resistance at 15 °C, α is the temperature coefficient of resistance, and ΔT is the temperature change. We want to solve this for ΔT:
R/R0 = 1 +α·ΔT
(R/R0 -1)/α = ΔT = (60/50 -1)/0.0043 ≈ 46.5 . . . . °C
The relay may fail to operate at temperatures above (15 +46.5) °C = 61.5 °C.
Answer:
Magnitude of velocity when s is 10 m= 4.58m/s
Magnitude of acceleration when s is 10 m = 0.653 m/s²
Explanation:
Radius of circular path = 50m
Speed = 4m/s
increase in acceleration = (0.05s)m/s²
speed and acceleration when s is 10 m = ?
Magnitude of Velocity:
From third equation of motion
Magnitude of Acceleration:
The tangential component of acceleration is
The normal component of acceleration is
Substituting tangential and normal component in (1)
a=0.653 m/s²
Answer:
1. General purpose file server.
2. Virtual Desktop Infrastructure Server.
3. Virtualized Backup Server.
All except : Database server
Explanation:
As a simple definition, we can tell, data deduplication is an elimination of redundant data in data set and storing only one copy of the same data. It is done by identifying double byte patterns through data analysis, removing double data and replacing it with reference pointed to stored, single piece of data.