Answer:
T₂ =93.77 °C
Explanation:
Initial temperature ,T₁ =27°C= 273 +27 = 300 K
We know that
Absolute pressure = Gauge pressure + Atmospheric pressure
Initial pressure ,P₁ = 300+1=301 kPa
Final pressure ,P₂= 367+1 = 368 kPa
Lets take temperature=T₂
We know that ,If the volume of the gas is constant ,then we can say that
![\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_2%7D%7BP_1%7D%3D%5Cdfrac%7BT_2%7D%7BT_1%7D)
![{T_2}=T_1\times \dfrac{P_2}{P_1}](https://tex.z-dn.net/?f=%7BT_2%7D%3DT_1%5Ctimes%20%5Cdfrac%7BP_2%7D%7BP_1%7D)
Now by putting the values in the above equation we get
![{T_2}=300\times \dfrac{368}{301}\ K](https://tex.z-dn.net/?f=%7BT_2%7D%3D300%5Ctimes%20%5Cdfrac%7B368%7D%7B301%7D%5C%20K)
The temperature in °C
T₂ = 366.77 - 273 °C
T₂ =93.77 °C
Answer: you can watch a video on how to solve this question on you tube
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