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3 years ago

The cost is 23$ when___coolers are produced

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

9514 1404 393

Answer:

Step-by-step explanation:

We want to find x when C = 23.

23 = 0.005x^2 -0.35x +10

2600 = x^2 -70x . . . . . . subtract 10, multiply by 200

2600 +35^2 = (x -35)^2 . . . . complete the square

61.847 +35 = x . . . . . . . square root, add 35 (use the positive result only)

x ≈ 97 . . . . rounded to integer

The cost is $23 when 97 coolers are produced.

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If one endpoint is (-6,4) and the midpoint is (4,8) what would be the other endpoint ???? if you can explain it would be great

krek1111 [17]

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3 years ago

The purpose of statistical inference is to make estimates or draw conclusions about a.

Free_Kalibri [48]

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2 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

To find when will the ball land, we set h=0

$2x^2-12x+20=0$

Simplifying by 2

$x^2-6x+10=0$

Completing squares

$x^2-6x+9+10-9=0$

Factoring and rearranging

$(x-3)^2=-1$

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

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3 years ago

Flying object hazard are specially dangerous when using power-actuated tools because

goblinko [34]

The tools couldn't have made the proper measurments

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3 years ago

Identify whether the series summation of 8 open parentheses 5 over 6 close parentheses to the i minus 1 power from 1 to infinity

Leto [7]

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3 years ago

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