Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8
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(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13
sina=3/√13, cosa=2/√13, tana=3/2
Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13
Answer:
3
Step-by-step explanation:
3(1)² - 5(1) + 1
3x3 = 9
9-5+1
9-6 = 3
The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:
y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.
Substituting the given info into the equation y-k = a(x-h)^2, we get:
3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is
y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.
Answer:
22 pi ft
Step-by-step explanation:
We can use the area to find the radius
A = pi r^2
121 pi = pi r^2
Divide each side by pi
121 = r^2
Take the square root
sqrt(121) = sqrt(r^2)
11= r
Now we need to find the circumference
C = 2*pi*r
C = 2* pi *11
C = 22 pi ft
