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Salsk061 [2.6K]
3 years ago
5

Classify the following compounds as binary ionic, ternary ionic, or molecular.

Chemistry
1 answer:
Alborosie3 years ago
3 0

Answer:bro u already have an answer why are you asking?

Explanation:

You might be interested in
Using the mmoles of (35)-2,2,-dibromo-3,4-dimethylpentane calculated earlier and the molecular weight of the product (962 g/mol)
Sedbober [7]

Answer:

The yield of the product in gram is \mathsf{{w_P}=0.26 \ gram}

Explanation:

Given that:

the molecular mass weight of the product = 96.2 g/mol

the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g

given that the millimoles of the reagent = 2,7 millimoles = 2.7 \times 10^{-3} \ moles

We know that:

Number of moles = mass/molar mass

Then:

2.7 \times 10^{-3} = \dfrac{ mass}{257.997}

mass = 2.7 \times 10^{-3} \times 257.997

mass = 0.697

Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100

i.e

Theoretical yield = \dfrac{n_P}{n_R}\times 100\%

where;

n_P = \dfrac{w_P}{m_P}    and n_R = \dfrac{w_R}{m_R}

Theoretical yield = \dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%

Given that the theoretical yield = 100%

Then:

100\% =\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%

\dfrac{w_P}{m_P}=\dfrac{w_R}{m_R}

{w_P}=\dfrac{w_R \times m_P}{m_R}

where,

w_P = derived weight of the product

m_P =the molecular mass of the derived product

m_R = the molecular mass of the reagent

w_R = weight in a gram of the reagent

{w_P}=\dfrac{w_R \times m_P}{m_R}

{w_P}=\dfrac{0.697 \times 96.2}{257.997}

\mathsf{{w_P}=0.26 \ gram}

8 0
3 years ago
Why does the atomic radius decrease across a period
IgorC [24]
Because the nuclear charge increases across a period and so it has a stronger pull on the outer electrons and will pull in the radius
4 0
2 years ago
Are alcohols with more than one hydroxyl group attached to a carbon sequence.
Darya [45]

Answer:

Polyhydroxyl alcohols

Explanation:

Whenever we have several C-OH bonds, we have a polyhydroxyl alcohol. For example, if we have just one alcohol group, that is, an R-OH group, then the naming is simple, say, we have EtOH, it's ethanol.

The problem becomes more complicated when we have several hydroxyl groups present in the alcohol. Let's say we have an ethane molecule and we replace the hydrogen atoms of carbon 1 and 2 with hydroxyl groups. In that case, we have 1,2-ethanediol. Similarly, we can have triols etc.

That said, we have poly (several) hydroxyl groups and we can generalize this to having polyhydroxyl alcohols.

5 0
3 years ago
Hi how are you today well have a great rest of your day
amid [387]

Answer:

I'm well and same to you

Explanation:

6 0
2 years ago
Read 2 more answers
Will give most brainly.
Anna [14]

Answer:

One mole

Explanation:

It tells u the concentration

8 0
2 years ago
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