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OLEGan [10]
3 years ago
10

Which of the following describes work?

Chemistry
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

  • <em><u>lifting a 1 kg mass 1 m.</u></em>

Explanation:

<em>Work </em>is the result of applying a force that manages to move a mass.

Thus, the work (mechanical work in this case because this is a mechanical force, not an electrical one) applied by a constant force is the product of the force times the distance that the object is moved.

Also, you can calculate the mechanical work as the difference in the mechanical energy between the initial and the final stages of the event where the force was applied.

Let's see each choice:

a) <em><u>Holding a mass for 1 hr</u></em>: since no translation is involved, displacement is and the work is zero.

b) <em><u>Holding 1 kg mass</u></em>: again, no motion is involved, so there is no work.

c) <em><u>Moving 1 m in 1 hr</u></em>: there is not force involved in this statement, so there is not work.

d) <em><u>lifting a 1 kg mass 1 m:</u></em> this, indeed, describes a situation where work results from applying a lifting force to move a mass 1 m up.

In this case, such work is equal to the change in the potential energy of the mass: mgΔh = 1kg × 9.8m/s² × 1 m = 9.8 joules.

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calculate the heat required in joules to convert 18.0 grams of water ice at a temperature of -20 c to liquid water at the normal
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Answer:

Explanation:

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In a reaction that occurs in solution, the volume will not change. What happens to the concentration of the reactants? What happ
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wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.
Papessa [141]

<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  A+2B\xrightarrow[]{K_1} 2C

<u>Equation 2:</u>  2C\xrightarrow[]{K_2} D

The net equation follows:

D\xrightarrow[]{K} A+2B

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K=K_1\times \frac{1}{K_2}

We are given:

K_1=2.57

K_2=0.226

Putting values in above equation, we get:

K=2.57\times \frac{1}{0.226}=11.37

Hence, the value of equilibrium constant for the net reaction is 11.37

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