All categories

3 years ago

Which of the following describes work?

Chemistry

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

lifting a 1 kg mass 1 m.

Explanation:

Work is the result of applying a force that manages to move a mass.

Thus, the work (mechanical work in this case because this is a mechanical force, not an electrical one) applied by a constant force is the product of the force times the distance that the object is moved.

Also, you can calculate the mechanical work as the difference in the mechanical energy between the initial and the final stages of the event where the force was applied.

Let's see each choice:

a) Holding a mass for 1 hr: since no translation is involved, displacement is and the work is zero.

b) Holding 1 kg mass: again, no motion is involved, so there is no work.

c) Moving 1 m in 1 hr: there is not force involved in this statement, so there is not work.

d) lifting a 1 kg mass 1 m: this, indeed, describes a situation where work results from applying a lifting force to move a mass 1 m up.

In this case, such work is equal to the change in the potential energy of the mass: mgΔh = 1kg × 9.8m/s² × 1 m = 9.8 joules.

You might be interested in

In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke

kondor19780726 [428]

Answer:

Explanation:

Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.

In the living E. coli cells,

[ATP] = 7.9 mM;

[ADP] = 1.04 mM,

[glucose] = 2 mM,

[glucose 6-phosphate] = 1 mM.

Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.

The reaction is given as

Glucose + ATP → glucose 6-phosphate + ADP

Now reaction quotient for given equation above is

$q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}$

$q=\frac{(1mm)\times (1.04 mm)}{(7.9mm)\times (2mm)} \\\\=6.582\times 10^{-2}$

so,

$q$ ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable until q = Keq

4 0

3 years ago

If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? A. SO3 +O2à SO3 B. 2SO2 + O2à 2SO3

ycow [4]

REVERSE REACTION WILL BE SO2+O2

7 0

3 years ago

Read 2 more answers

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

Answer: The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

Explanation:

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago

A rocket is designed to drop its first stage mid-flight. Due to a malfunction, this does not occur. What is a possible result of

artcher [175]

Answer:

The rocket is now too heavy to reach its destination.

3 0

3 years ago

Read 2 more answers

14 points!!! Pls tell me answer :3

iren [92.7K]

I’d say the last one

8 0

3 years ago

Read 2 more answers