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3 years ago

TRUE or FALSE: The charge of an atom (ion) is determined by the ratio of electrons to protons.

2 answers:

8 0

True The positive electric charge of a proton is equal in magnitude to the negative charge of an electron; therefore, the net electric charge of an ion is equal to its number of protons minus its number of electrons. Ions are highly reactive species.

zubka84 [21]3 years ago

5 0

The answer would be false

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Consider the following balanced equation:3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)If 24.2 moles of Na3PO4(aq) reac

Tomtit [17]

Answer:

69.7% is percent yield

Explanation:

Based on the reaction:

3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)

2 moles of Na3PO4 react producing 6 moles of NaNO3.

As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:

24.2 moles Na3PO4 * (6 moles NaNO3 / 2 moles Na3PO4) =

72.6 moles of NaNO3

As there are produced 50.6 moles of NaNO3, percent yield is:

50.6 moles NaNO3 / 72.6 moles NaNO3 =

<h3>69.7% is percent yield</h3>

7 0

2 years ago

How many atoms are there in 1 g of argon?

amm1812

Answer:

1.5057×10^22 atom

Explanation:

As we

1 mole of argon = 40 g of argon

i.e 40 g of argon = 1 mole of argon

1 g of argon = 1/40 mole of argon

1 mole of argon = 6.023×10^23 atom of argon

1/40 mole if argon = 1/40 ×6.023×10^23

= 1.5057×10^22

7 0

2 years ago

What information does the first quantum number of an electron give?

bazaltina [42]

Answer:

Explanation:

the first quantum number of an electron gives the information about the energy level the electron is in

4 0

2 years ago

How many moles of atoms are in 9.00 g of 13c?

Blababa [14]

<span>The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So, 9.00 g / 13.0 g/mol = 0.692 moles Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.</span>

8 0

3 years ago

Read 2 more answers

A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to

grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0

3 years ago