The area is 36 units squared.
You have three ways you can solve this question.
Method 1:
Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.
Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.
A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36
Method 2:
Calculate the length of DP.
The length of line segment DP is √28.8
Calculate the length of DC.
The length of line segment DC is 3√5
Put into equation A = bh.
A = bh
A = 3√5(√28.8)
A = 36
Method 3:
Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)
Diagonal DB = 12 units
Diagonal AC = 6 units
A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36
I love procrastinating my history essay for this :D
Answer:
1
/27
1 over 27
Step-by-step explanation:
brainliest please?
The answer is A.5/8.
Why?
Multiply 1/4 with 2/2 to get the same denominator as 7/8, 8. That will yield 2/8.Then, simply subtract 2/8 from 7/8 (7/8 - 2/8), and that equals 5/8.
Hope this helps!
Answer:
The measure of the third arc is 
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
----> equation A
-----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z
Blue was not the imposter.
