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3 years ago

There is a vector A with magnitude 5 units pointing toward west, and a

Physics

1 answer:

Anit [1.1K]3 years ago

4 0

Using the Pythagorean’s theorem to find the resultant, we find 5’2 +3’2=x’2
X=square root of 34=5.8unitd

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Need help!!!<br> Physics due tomorrow help, help ,help

Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

$F_{net}=F_{1}-F_{2}=26-8=14N$

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

$F_{x}=Fsin ($ θ $)= 67sin(73)=64N$

then, as Q(1),

$F_{net}=F_{1}-F_{2}=64-33=31 N$

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

$F_{Tension}=420 N$

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

$F_{x}=Fsin ($ θ $)= 600sin(45)=424.264N$

$F_{y} = F sin ($ θ $)= 600cos45)=424.264N$

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

$F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N$ in east

$F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N$ in south

The total net force for perpendicular forces is calculated from the relation:

$F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N$

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = $tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}$

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, $F_{right}=F_{left}=55N$

7 0

4 years ago

Who developed radiometric dating? What age did he assign to the oldest rocks?

Mekhanik [1.2K]

Ernest Rutherford
don't know the age sorry

5 0

3 years ago

¿De qué altura cae un cuerpo que tarda 4 s en llegar al suelo? usar g = 10 m/s2 *

jasenka [17]

Answer:

Explanation:

3 0

3 years ago

A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases

Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, $\rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}$

Change in Pressure in the tank, $\Delta P = 7.28\ mmHg$

Density of the mercury, $\rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}$

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

$\Delta P = 7.28\ times 133.332 = 970.656\ Pa$

Also,

$\Delta P = \rho_{o} gh$

where

g = acceleration due to gravity

h = height of the fluid level

$970.656 = 900\times 9.8\times h$

h = 0.11 m

Now, if mercury is used:

$\Delta P = \rho_{m} gh$

$970.656 = 13600\times 9.8\times h$

h = 0.00728 m = 7.28 mm

3 0

4 years ago

A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How

mr_godi [17]

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

$F=ma$

Plug in the given values and solve for force 'F' acting on the object. This gives,

$F=(10\ kg)(5\ m/s^2)\\\\F=50\ N$

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

$W=FS$

Plug in the values given and solve for 'W'. This gives,

$W=50\ N\times 20\ m \\\\W=1000\ J$

Therefore, the work done by the force is 1000 J.

7 0

4 years ago