Answer:

Explanation:
<u>Given Data:</u>
Acceleration due to gravity = g = -9.8 m/s²
Maximum Height = h = 0.490 m
At h,
= 0
<u>Required:</u>

<u>Formula:</u>

<u>Solution:</u>
Put the givens
![2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=2%20%28-9.8%29%20%280.490%29%20%3D%20%280%29%5C%C2%B2%20-%20v_o%5E2%5C%5C%5C%5C-9.604%3D-v_o%5E2%5C%5C%5C%5C9.604%3Dv_o%5E2%5C%5C%5C%5CTake%20%5C%20sqrt%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Csqrt%7B9.604%7D%3Dv_o%5E2%5C%5C%5C%5C3.1%20%5C%20m%2Fs%3Dv_o%5C%5C%5C%5Cv_o%3D3.1%5C%20m%2Fs%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Three of these are strong electrolytes:
- HCl (Hydrochloric acid)
- HNO3 (Nitric acid)
- NaOH (Sodium hydroxide)
Two of these are Weak electrolytes:
- HF (Hydrogen fluoride)
- HC2H3O2 (Acetic acid)
And the other two are Non-electrolytes:
- C6H12O6 (Glucose)
- C2H5OH (Ethanol)
We can find the x-component of the force vector, so Fx = 25N(cos30). Then, we can sub this into the work equation W = Fs or W = Fd.
Therefore, W = (25N(cos30))(3m) = 64.95 J.
With sig figs, it is 60 J.