By using this formula of vapor pressure:
Pv(solu)= n Pv(water)
when we have Pv(solu)=231.16 torr & Pv(water)= 233.7 torr
from this formula, we can get n (mole fraction of water) by substitution:
231.16 = n * 233.7
∴ n(mole fraction of water) = 0.99
so mole fraction of solution = 1 - 0.99 = 0.01
when no.of moles of water = mass weight / molar weight
= 365g / 18g/mol = 20 moles
Total moles in solution = moles of water / mole fraction of water
= 20 / 0.99 =20.2
no. of moles of the solution= total moles in solution- moles of water
= 20.2 - 20 = 0.2 moles
when we assumed the mass weight of the solution = 16 g (missing in your question should be given)
∴ molar mass = mass weight of solute / no. of moles of solute
= 16 g / 0.2 mol = 80 g/mol
Answer:
Molecular Weight Of KAl(SO4)2 12H2O = 475 G / Mol Molecular Weight Of Al = 27 G / Moles.
Explanation:
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Answer: The student should have worn splash goggles, an apron, and gloves during the investigation.
Explanation:
The length of the rug in cm will be
46.3 in = 117.602 cm
Answer: option B. The number of the outer most energy level for elements in that period
Explanation:
