In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
<span>7.75% nitrogen in the sample.
The balanced reaction of HCl and NH3 is
HCl + NH3 = NH4Cl
Which means that 1 mole of HCl will neutralize 1 mole of HN3.
Since we used 83.0 ml of 0.150 m HCl, that means that we used
0.083 l * 0.150 mol/l = 0.01245 mol
So we had 0.01245 mol of NH3 which means that we had 0.01245 mol of N
Looking up the atomic weight of nitrogen, we get 14.0067. So
0.01245 * 14.0067 = 0.174383415 g
We now know that the sample had 0.17438 g of nitrogen. Divide by the original mass of the sample, getting
0.17438 / 2.25 = 0.077502222 = 7.7502222%
Rounding the result to 3 significant figures, gives us a mass percentage of 7.75% nitrogen in the original sample.</span>
Answer:
Sodium chloride is ionically bonded. An electron has transferred from sodium to chlorine. Sodium has an electronegativity of 1.0, and chlorine has an electronegativity of 3.0.
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D.radiation that’s the right answer