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3 years ago

PLEASE HELP FAST!!!!

Chemistry

1 answer:

marissa [1.9K]3 years ago

4 0

Answer:

See detailed explanation.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to tell that neutralization reactions are usually double replacement reactions whereby an acid reacts with a base, commonly a hydroxide, in order to obtain a salt product and water.

They are called neutralization because they look for the neutral pH, 7, as a result of the reaction. Thus, the aforementioned can be depicted by bearing to mind the example of the neutralization of hydrochloric acid with sodium hydroxide to yield sodium chloride (salt) and water:

$HCl+NaOH\rightarrow NaCl+H_2O$

Regards!

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2 years ago

(A) H2SeO4(aq) + 2 Cl-(aq) + 2 H+(aq) → H2SeO3(aq) + Cl2(g) + H2O(l) (B) S8(s) + 8 O2(g) → 8 SO2(g) (C) 3 Br2(aq) + 6 OH-(aq) →

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Answer:

Explanation:

Oxidation occurs when the Nox number increases and a reduction occurs when the Nox number decreases. So, let's verify in which reaction the same reactant has elements that both occur after the reaction.

A) H₂SeO₄: H = +1, O = -2 (fixed)

Se: x +2*1 + 4*(-2) = 0

x + 2 - 8= 0

x = +6

Cl⁻: -1 (ions have Nox equal to its charge)

H⁺: +1

H₂SeO₃: H = + 1, O = -2

Se: x +2*1 + 3*(-2) = 0

x + 2 -6 = 0

x = + 4 (Se reduces)

Cl₂: Cl = 0 (simple molecule, so Cl oxides)

H₂O: H = +1, O = -2

B) S₈: S = 0

O₂: O = 0

SO₂: O = -2, S: x + 2*(-2) = 0 -> x = +4 (S oxides and O reduces)

C) Br₂: Br = 0

OH⁻ : O = -2, H = +1

Br⁻ = -1 (Br reduces)

BrO₃⁻: O = -2, Br: x +3x(-2) = -1 -> x = +5 (Br oxides)

H₂O: H = +1, O = -2

D) Ca²⁺: Ca = +2

SO₄²⁻: O = -2, S: x +4*(-2) = -2 -> x = +6

CaSO₄: O = -2, S = +6, Ca = +2

E) PtCl₄: Cl = -1 (fixed), Pt: x + 4*(-1) = 0 -> x = +4

Cl⁻: Cl = -1

PtCl₆²⁻: Cl = -1, Pt = x + 6*(-1) = -2 -> x = +4

So, only in letter C Br₂ is undergoes both oxidation and reduction.

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3 years ago

True or False

Alexxandr [17]

Answer:

Its 26. True

27 . False

Explanation:

hope it helps !

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