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Free_Kalibri [48]
2 years ago
8

The state of matter in which a material has a definite shape and a definite volume is the _____ state.

Chemistry
1 answer:
Scilla [17]2 years ago
3 0

Answer:

solid

Explanation:

in the solid state the material will has a fixed shape and volume whatever the container that contains it

where in liquid the shape will be different depending on the container

and in gas state the shape and volume are not definite

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A sample of krypton gas with a volume of 10.00 L has a temp of 303 K and exerts
marshall27 [118]

<u>Answer:</u> The final volume will be 14.85 L.

<u>Explanation:</u>

To calculate the final volume when temperature increases, we use Charles' Law.

This law states that volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.

V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 = Initial volume and temperature

V_2\text{ and }T_2 = Final volume and temperature

We are given:

V_1=10L\\&#10;T_1=303K\\&#10;V_2=?L\\&#10;T_2=450K

Putting values in above equation, we get:

\frac{10L}{303K}=\frac{V_2}{450K}

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7 0
3 years ago
How many moles are in 23.4 g
-BARSIC- [3]

Answer: 1 mole

Explanation:

6 0
3 years ago
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the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the hydrogen gas collected occupies 14 L at 3
juin [17]

Answer:

Pressure for H₂ = 11.9 atm

Option 5.

Explanation:

We determine the complete reaction:

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As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.

Ratio is 2:3.

2 moles of Al, can produce 3 moles of hydrogen

Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles

Now we can apply the Ideal Gases law to find the H₂'s pressure

P . V  = n . R . T → P = (n . R .T) / V

We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L

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3 years ago
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30 POINTS PLEASE HELP ASAP
lina2011 [118]

Hello!

We have the following data:

f (radiation frequency) = 3.0*10^{19}\:Hz

v (speed of light) = 3.0*10^8\:m/s

λ (wavelength) = ? (in m)

Let's find the wavelength, let's see:

f = \dfrac{v}{\lambda}

3.0*10^{19} = \dfrac{3.0*10^8}{\lambda}

\lambda = \dfrac{3.0*10^8}{3.0*10^{19}}

\boxed{\boxed{\lambda = 1*10^{-11}\:m}}\Longleftarrow(wavelenght)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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3 years ago
Ignoring cis-/trans- specifications, what is the IUPAC name for the following structure?
bixtya [17]

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