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Mama L [17]
2 years ago
6

Un cuerpo de 3,5 kg se encuentra en reposo sobre un plano inclinado 37o. Está sujeto al extremo superior del plano inclinado med

iante un muelle de constante recuperadora 15 N/m. Sabiendo que el coeficiente de rozamiento vale 0,6, calcula el alargamiento del muelle. Sol: 42 cm.
Physics
1 answer:
Tems11 [23]2 years ago
8 0

Answer:

1,1 m

Explanation:

Dado que;

coeficiente de fricción = 0,6

sabemos que W = R = mgcos 37 = 3.5Kg * 10m / s ^ 2 * cos37 = 27.95 N

coeficiente de fricción = fuerza / reacción normal (R)

Fuerza = 0.6 * 27.95 N

Fuerza (F) = 16.77 N

Recuerda que F = Ke

dónde;

K = constante de fuerza (15N / m)

e = extensión (lo desconocido)

e = F / K

e = 16,77 N / 15 N / m

e = 1,1 m

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4 0
3 years ago
What would the electrostatic force be for two 0.005C charges 50m apart?
irakobra [83]

Answer:

90 N

Explanation:

The electrostatic force between two charges is given by:

F=k\frac{q_1 q_2}{r^2}

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In this problem we have

q1 = q2 = 0.005 C

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So the electrostatic force is

F=(9\cdot 10^9 N m^2 C^{-2})\frac{(0.005 C)^2}{(50 m)^2}=90 N

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3 years ago
A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti
Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: Vf^{2} = Vo^{2} - 2gh and h=Vo*t - \frac{g*t^{2} }{2}, First we need to find the height to time iqual to 3.04 s using the formula: h=Vo*t - \frac{g*t^{2} }{2} and remember that golf ball was released from the rest (Vo= 0 (m/s)) so h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}, we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using Vf^{2} = Vo^{2} - 2gh solving for Vf, we get: Vf = \sqrt{Vo^{2}-2*g*h } replacing the values given Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }, so we get: Vf = 29.79 (m/s).

5 0
3 years ago
Read 2 more answers
Una barra de aluminio que esta a 78 GRADOS CENTIGRADOS entra en contacto con una barra de cobre de la misma longitud y área que
stiks02 [169]

Answer:

Al llegar a su equilibrio térmico ambas barran tendrán una temperatura de 53 grados centígrados.

Explanation:

Dado que una barra de aluminio que está a 78 grados centígrados entra en contacto con una barra de cobre de la misma longitud y área que esta a 28 grados centígrados, y posteriormente se lleva acabo la transferencia de energía entre ambas barras llegando a su equilibrio térmico, para determinar la temperatura a la que ambas barras llegarán se debe realizar el siguiente cálculo:

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53 = X

Por lo tanto, al llegar a su equilibrio térmico ambas barran tendrán una temperatura de 53 grados centígrados.

8 0
3 years ago
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