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Alex
2 years ago
11

1. What would you be wearing on the Mercury?

Chemistry
1 answer:
Vikentia [17]2 years ago
7 0

Answer:

This planet rules communication, education, and commerce. Wednesdays is a day to tend the mind and care for the self. What to Wear: Mercury is represented by the color green, so wear something green on Wednesdays, be it a piece of jewelry with an emerald stone or your favorite pair of Chuck Taylors

2Metallic mercury mainly causes health effects when inhaled as a vapor where it can be absorbed through the lungs. Symptoms of prolonged and/or acute exposures include: Tremors; Emotional changes (such as mood swings, irritability, nervousness, excessive shyness)

3The four basic needs of nearly all survival situations are shelter, water, fire, and food

You might be interested in
33 grams of NH4NO3 will produce how many grams of water
Leni [432]

Answer:

66 grams

Explanation:

For every 1 gram of NH4NO3 equals 2 grams of water

8 0
3 years ago
6. _atom a. shows the elements and ratio of atoms in a
Roman55 [17]

Answer: In the first paragraph, name a theme of Paul Laurence Dunbar's poem "Sympathy," and explain how it develops, citing specific examples

Explanation:

8 0
2 years ago
Calculate the final Celsius temperature when 634 L at 21 °C is compressed to 307 L.
Illusion [34]

Answer:

- 130.64°C.

Explanation:

  • We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

V₂ = 307.0 L, T₂ = ??? K.

<em>∴ T₂ = V₂T₁/V₁ </em>= (307.0 L)(294.0 K)/(634.0 L) = <em>142.36 K.</em>

<em>∴ T₂(°C) = 142.36 K - 273 = - 130.64°C.</em>

5 0
3 years ago
Which element has the electron configuration [Rn] 7s2 5f14 6d4 ?
nexus9112 [7]

Answer:

Rn] 5f14 6d4 7s2 mp: none d: none. Seaborgium ..... Element. Density. Boiling or Melting Point in °C. Electron Configuration. Symbol.

Explanation:

3 0
3 years ago
Read 2 more answers
Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i
gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

V_{hydrogen = 2 × 4/3 × π × r_{H}^{3}

where r_{H}^{3} = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × 10^{-12} meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

7 0
3 years ago
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