Ask question

Ask question

All categories

2 years ago

13

Which describes reproducibility

1 answer:

Leya [2.2K]2 years ago

6 0

Reproducibility is a major principle of the scientific method. It means that a result obtained by an experiment or observational study should be achieved again with a high degree of agreement when the study is replicated with the same methodology by different researchers.

You might be interested in

For every 1.0 mole of glycine in the sample, how many molecules of methionine are present? (for help performing calculations wit

krok68 [10]

1.08 X 10^21 molecules

3 0

3 years ago

How many moles of CO gas are in 34.6 L?

Troyanec [42]

moles of CO gas : 1.545

<h3>Further explanation</h3>

Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions

There are 2 conditions that are usually used as a reference : STP and RTP

Assuming the STP state :

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

Then for 34.6 L of CO gas :

$\tt moles=\dfrac{34.6}{22.4}=1.545$

6 0

2 years ago

Please help, with step by step work

natali 33 [55]

$\qquad$ ☀️ $\pink{\bf{ {Answer = \: \: 85.57g }}}$

Molar mass of $\bf Cu_2O$

$\qquad$ $\twoheadrightarrow\sf 63.546 \times 2 +16$

$\qquad$ $\pink{\twoheadrightarrow\bf 143.092 g}$

<u>As we know</u>–

1 mol = $\bf 6.02×10^{23}$ formula units

1 mol $\bf Cu_2O$ = 143.092 g = $\bf 6.02×10^{23}$ formula units

Henceforth –

$\bf 3.60×10^{23}$ formula units $\bf Cu_2O$ –

$\qquad$ $\sf :\implies \dfrac{143.092 \times3.60×10^{23 }}{6.02×10^{23}}$

$\qquad$ $\sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23 }}}{6.02×\cancel{10^{23}}}$

$\qquad$ $\pink{:\implies\bf 85.57 g}$

5 0

2 years ago

In a chemical change, the substance that you end up with is the

elena55 [62]

The reactant is what you begin with.
The product is what you end up with (so the answer is B)

3 0

3 years ago

Read 2 more answers

A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy were trans

Brut [27]

The final temperature : 78.925°C

<h3>Further explanation </h3>

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Energy releases = 130 kcal = 130 x 4.18 kJ=543.4 kJ

The final temperature :

$\tt \Delta T=\dfrac{Q}{m.c}\\\\\Delta T=\dfrac{543.4}{2.5\times 4.186~kJ/kg^oC}\\\\\Delta T=51.925^oC$

Final temperature :

ΔT=final-initial

51.925°c=final-27°c

final = 51.925+27=78.925°C

7 0

2 years ago