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3 years ago

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The percent composition of methyl butanoate is 58.8% C, 9.8% H, and 31.4 % O and its molar mass is 102 g/mol. What is its empiri

cal formula? What is its molecular formula?

1 answer:

yanalaym [24]3 years ago

3 0

Methyl Butanoate has a molecular formula of C6H12O2 and an empirical formula of C3H6O

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Explanation:

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3 years ago

Which of the following shows the 3 main jobs of a cell?

skad [1K]

C is the answer hope this helps

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2 years ago

The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w

Natali [406]

The partial pressure of gas C is 0.902 atm

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partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]

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3 years ago

Read 2 more answers

What happen when you add heat to solids and liquids?

sasho [114]

When you add heat to a solid the particles gain energy and start to vibrate faster and faster.
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2 years ago

Read 2 more answers

Need help !!!!! ASAP

gavmur [86]

<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

$T_{2}=4K$

<h2>Why?</h2>

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

So, we are given the following information:

$V_{1}=500mL\\T_{1}=20K\\V_{2}=100mL$

Then, isolating the new temperature and substituting the given information, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

$T_{2}=\frac{T_{1}}{V_{1}}*V_{2} \\$

$T_{2}=\frac{20.00K}{500mL}*100mL\\$

$T_{2}=4K$

Hence, the new temperature will be equal to 4 K.

$T_{2}=4K$

Have a nice day!

7 0

3 years ago