three carbon is the most reactive
The ending carbon atoms of an extended aliphatic chain can combine in organic chemistry to create a closed system or ring, which results in cycloalkanes. These substances are referred to as cyclic substances. Cyclopropane, cyclobutane, cyclopentane, among many more, are examples.
Since cyclopropane has rings in its structural arrangement, it is less stable than the other cycloalkanes mentioned above. The positional orientation of the atoms of cycloalkane compounds, which have a tendency to emit a very high and unfavorable energy, is known as the ring strain. The ring becomes unstable and reactive due to the release of heat energy that has been trapped in its bonds and molecules.
The smaller cycloalkanes are more significantly impacted by the ring strain in terms of their structural makeup and conformational behavior.
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Answer:
Explanation:
Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)
Explanation;
According to Arrhenius equation:
i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)
Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K
T2 = 25 oC = (25 + 273) K = 298 K
i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)
i.e. ln(k2/0.000717) = -2.54738
i.e. k2/0.000717 = 
= 0.078286
Therefore, the required constant (k2) = 0.078286 * 0.000717 = 
Answer:
Explanation:
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