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mr Goodwill [35]
3 years ago
14

Sofia has 25 coins in nickels and dimes in her pocket for a total of $1.65 how many of each type of coin does she have?​

Mathematics
2 answers:
Simora [160]3 years ago
8 0

Answer:

She has 23 nickels and 5 dimes.

Step-by-step explanation:

Let n = the number of nickles and d = the number of dimes.

The number of each = 28. Set up the equation:

n + d = 28

Solve for n:

n = 28 - d

The total amount is $1.65 or 165 cents:

5n + 10d = 165

Substitute:

5(28 - d) + 10d = 165

140 - 5d + 10d = 165

140 + 5d = 165

5d = 165 - 140

5d = 25

d = 5, the number of dimes.

Solve for n:

n = 28 - d

n = 28 - 5 = 23, the number of nickles.

Proof:

5n + 10d = 165

5(23) + 10(5) = 165

115 + 50 = 165

165 = 165

Hope this Helps! Have an Awesome Day!!! <3

Step-by-step explanation:

uysha [10]3 years ago
7 0

Answer:

Sofia has <u>23 nickles & 5 dimes</u>

Step-by-step explanation:

The number of each is 28

Form an equation:

n+d=28

Solve for n:

n=28-d

The total amount is $1.65 for 165 cents:

5n+10d=165

Substitute:

5(28-d)+10d=165

140-5d+10d=165

140+5d=165

5d=165-140

5d=25

d=25/5

d=5

Solve for n:

n=28-d

n=28-5=23 ⇒ the number of nickles

<u>CHECK:</u>

5n+10d=165

5(23)+10(5)=165

115+50=165

165=165

<em>hope this helps....</em>

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