Question

Sofia has 25 coins in nickels and dimes in her pocket for a total of $1.65 how many of each type of coin does she have?​

Answer 1

Answer:

She has 23 nickels and 5 dimes.

Step-by-step explanation:

Let n = the number of nickles and d = the number of dimes.

The number of each = 28. Set up the equation:

n + d = 28

Solve for n:

n = 28 - d

The total amount is $1.65 or 165 cents:

5n + 10d = 165

Substitute:

5(28 - d) + 10d = 165

140 - 5d + 10d = 165

140 + 5d = 165

5d = 165 - 140

5d = 25

d = 5, the number of dimes.

Solve for n:

n = 28 - d

n = 28 - 5 = 23, the number of nickles.

Proof:

5n + 10d = 165

5(23) + 10(5) = 165

115 + 50 = 165

165 = 165

Hope this Helps! Have an Awesome Day!!! <3

Step-by-step explanation:

Answer 2

Answer:

Sofia has 23 nickles & 5 dimes

Step-by-step explanation:

The number of each is 28

Form an equation:

$n+d=28$

Solve for n:

$n=28-d$

The total amount is $1.65 for 165 cents:

$5n+10d=165$

Substitute:

$5(28-d)+10d=165$

$140-5d+10d=165$

$140+5d=165$

$5d=165-140$

$5d=25$

$d=25/5$

$d=5$

Solve for n:

$n=28-d$

$n=28-5=23$ ⇒ the number of nickles

CHECK:

$5n+10d=165$

$5(23)+10(5)=165$

$115+50=165$

$165=165$

hope this helps....