Two pipes move the same amount of ideal fluid in the same amount of time. One pipe has a 2 in. diameter; the other has a 3 in. d
1 answer:
Answer:
a) 3-in. pipe
Explanation:
Given that
Fluid flow is in same amount in the same time it means that volume flow rate is same for the pipes
Volume flow rate
Q = A V
A=Area ,V=Velocity
If diameter d is more then the velocity will be less for same volume flow rate .We also Know that if pressure is more then the velocity will be less.
The second pipe 3 in diameter having more diameter then the velocity will be less but the pressure will be more.
That is why the 3 in diameter is having more pressure than 2 in diameter pipe.
Therefore the answer will be a.
a) 3-in diameter pipe
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Answer:
Check body of the explanation
Explanation:
Ooook, quick theory rushdown. if you're at a depth of h in a tank of a fluid, the pressure is the sum of the atmosferic pressure (if the tank is open on top) plus a term which is the product of acceleration of gravity - about , the density of whatever you're sinking in, and the depth at which you are. In formula,
, and the pressure is the same for every point of the tank at the same depth.
At this point, we can start answering!
1a. The pressure at A is - not counting atmosferic pressure - , while in B is
, so it's half of it.
1b. The two points are at the same depth, so the pressure is the same - they would be even if the two cilinders weren't linked!
1c. Ditto. Same depth? same pressure!
1d. Usual equation, this time density is 800. Pressure is : Since the density is 4/5 of water, the pressure is also 4/5 of the one exerted by water
2a. The volume is simply the product, so
2b. Density is defined as mass over volume, so you simply multiply the volume you found earlier by the density of paraffine:
2c. Weight is defined as the mass of something times the acceleration due to gravity, in our case it's
2d. again, what a surprise!
3. Yet again, .
I attached the missing picture.
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
There two forces acting on the child. The first one is the gravitational force and the second one is centrifugal force. In this example, the force of gravity is always pulling down, but centrifugal force always acts away from the center of circular motion.
Part A
For point A we have:
In this case, the forces are aligned, centrifugal is pointing up and gravitational is pulling down.
Part B
At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance:
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
There two forces acting on the child. The first one is the gravitational force and the second one is centrifugal force. In this example, the force of gravity is always pulling down, but centrifugal force always acts away from the center of circular motion.
Part A
For point A we have:
In this case, the forces are aligned, centrifugal is pointing up and gravitational is pulling down.
Part B
At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance: