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Trava [24]
4 years ago
5

A small fan has blades that have a radius of 0.0600 m. When the fan is turned on, the tips of the blades have a tangential accel

eration of 20.0 m/s2 as the fan comes up to speed. What is the angular acceleration α of the blades?
Physics
1 answer:
yaroslaw [1]4 years ago
3 0

Answer:

α = 333 m/s^2

Explanation:

Radius = 0.0600m

Tangential acceleration (a) = 20.0m/s^2

Angular acceleration (α) = ???

Angular acceleration describes the motion of the entire object. The tangential acceleration describes the motion of a single point on the object. Tangential acceleration is proportional to the radius and the angular acceleration.

a = rα

α = a/r

α = 20/0.06

α = 333.33 m/s^2

α = 333m/s^2

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The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object
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Answer:

C

Explanation:

Because this same question was on my test last week and I got it correct

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3 years ago
If the mass of the products measured 120 g, what would be the mass of the reactants? 30 g 60 g 120 g 240 g
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Answer:

The correct answer option is C

Explanation:

In a balanced chemical reaction mass of the reactant are always equal to mass of the products. Also known as Law of Conservation of Mass  which states that " mass can nor be created nor be destroyed in a chemical reaction."

So, the mass of the reactant will be equal to the mass of products.That is 120 grams.

Hence, the correct answer option(C).

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3 years ago
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The formation of a cell plate is a characteristic of
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The formation of a cell plate is a characteristic of cytokinesis in terrestrial plants.
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3 years ago
The question is given in the picture below.... please help me and mention all the steps..​
I am Lyosha [343]

Answer:

a)water is turning into ice it is changing it's state from liquid to solid

b)B to C  ice is melting and it  is changing  it's state from solid to liquid

C to D water is boiling and it is changing it's state from liquid to vapours(steam)

c) temperature

At A 0

At B 0

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At D 100

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8 0
3 years ago
Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec
SOVA2 [1]

Answer:

F_{net} = 6.879\times 10^{- 7}\ N

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

F = \frac{GMm}{\frac({d}{2}^{2})}

F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

F = \frac{GMm}{\frac({d}{2}^{2})}

F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

F_{net} = F + F'

F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N

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