That's the definition of pressure ... force on a given area.
So when that force increases, it's an increase in pressure.
v = speed of car = 90 km/h
u = speed of truck = 50 km/h
d = initial separation distance = 100 m = 0.1 km
They meet at time t such that
vt = d + ut
t(v - u) = d
t = d/(v - u) = (0.1 km) / [(90 - 50) km/h] = 0.0025 hours
2.1 x 102
Is the correct solution for this problem
Answer:
Explanation:
for vertical movement , time to reach the top = time to reach the hand = 2.5 s
v = u - gt
At the top , v = 0 , time t = 2.5 s
0 = u - g x 2.5
u = 2.5 x 9.8 = 24.5 m /s
velocity of throw = 24.5 m /s
So , when it passes the hand on its way down , it will have velocity equal to 24.5 m /s and it will accelerate downwards . Let its velocity down by 22 m be v
v² = u² + 2 g s
= 24.5² + 2 x 9.8 x 22
= 600.25 + 431.2
= 1031.45
v = 32.11 m /s .
Explanation :
Using the law of conservation of energy
When two cars collide with each other then the momentum is same before collision and after collision but energy is changed after collision in form of heat and sound.
We know this collision is inelastic collision.
In Inelastic collision, when two objects collide with each other then the momentum is conserved but kinetic energy is not conserved.
