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4 years ago

The force of gravity down on the boy= 300N

Physics

2 answers:

Leviafan [203]4 years ago

8 0

The net force on the boy is zero.

Based on this analysis, I would expect the boy to <u>not accelerate</u>.

kompoz [17]4 years ago

3 0

The net force of the boy is 300N=><=300N which equals a net force of 0N.

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A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00 ∘C∘C, the resistance of the carbo

likoan [24]

<h2>Answer:</h2>

16°C

<h2>Explanation:</h2>

The equation relating temperature with resistance is given as follows;

$R_{T}$ = $R_{0}$ [ $\alpha$ ( $T^{}$ - $T_{0}$ ) + 1] --------------(i)

<em>Where;</em>

$T_{0}$ = Temperature at some reference point

$R_{0}$ = Resistance at the reference point

T = Temperature at some other point

$R_{T}$ = Resistance at the other point

$\alpha$ = constant called "temperature coefficient of the resistor material"

<em>From the question; </em>

Let's take the reference point temperature ( $T_{0}$ ) as 4.00°C;

Therefore;

$R_{0}$ = Resistance at the reference point = 217.4Ω

$R_{T}$ = Resistance at the other point = 216.0Ω

$\alpha$ = Temperature coefficient of the resistor material (carbon) = -0.0005/°C

<em>Now substitute these values into equation (i) as follows;</em>

216.0 = 217.4 [(-0.0005)( $T^{}$ - 4) + 1]

216.0 = 217.4 [-0.0005 $T^{}$ + 0.002 + 1]

216.0 = 217.4 [-0.0005 $T^{}$ + 1.002]

<em>Divide through by 217.4 as follows;</em>

0.994 = 1.002 - 0.0005T

<em>Solve for T;</em>

0.0005T = 1.002 - 0.994

0.0005T = 0.008

T = 0.008 / 0.0005

T = 16°C

Therefore, the temperature on a spring day at that resistance is 16°C

4 0

3 years ago

Heat gained or lost is mass times specific heat times change in temperature.

BlackZzzverrR [31]

the answer would be B

6 0

3 years ago

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Annette [7]

The answer would be “A”

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4 years ago

Virtual image formed by concave mirror<br>

Elis [28]

Answer:

yes

Explanation:

because it is a diverging mirror

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3 years ago

How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00

klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is $9 \times 10^{-4} m^{2}$ . As the capacitance of capacitor is given as follows.

C = $\frac{\epsilon_{o}A}{d}$

It is known that the dielectric strength of air is as follows.

E = $3 \times 10^{6} V/m$

Expression for maximum potential difference is that the capacitor can with stand is as follows.

dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

Q = CV

= $\frac{\epsilon_{o} A}{d} \times E \times d$

= $\epsilon_{o}AE$

= $8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}$

= $1.062 \times 10^{-8} C$

or, = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0

4 years ago