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Alina [70]
3 years ago
14

A heavy sled and a light sled, both moving horizontally with the same speed, suddenly slide onto a rough patch of snow and event

ually come to a stop. The coefficient of kinetic friction between the sleds and the rough snow is the same for both of them.
Which of the following statements about these sleds are correct?

A) Both sleds will slide the same distance on the rough snow before stopping.

B) The heavy sled will slide farther on the rough snow than the light sled.

C) The light sled will slide farther on the rough snow than the heavy sled.

D) The friction from the snow will do the same amount of work on both sleds.
Physics
2 answers:
Alex777 [14]3 years ago
5 0

Answer:

A) Both sleds will slide the same distance on the rough snow before stopping.

D) The friction from the snow will do more negative work on the heavy sled than on the light sled.

Explanation:The coefficient of kinetic friction is the ratio of the force of friction of a given object or material to the normal force acting on it,it depends mainly on the nature of the surface in consideration. The higher the roughness of a surface is, the higher the coefficient of kinetic friction. For an object at rest on a plane surface with no other force acting on it,the normal force will be considered as the force of gravity.

maria [59]3 years ago
4 0

Answer:

The correct answers is option A) "Both sleds will slide the same distance on the rough snow before stopping".

Explanation:

For objects moving horizontally at the same speed, an equal coefficient of kinetic friction would mean that both objects will move the same distance before stopping, independently of their mass. The coefficient of kinetic friction is obtain from dividing the force needed to pull an object between the force that holds or prevents the object from moving. The coefficient of kinetic friction is a dimensionless scalar, which means that is independent of the size of the object because it depends only in the forces that act upon it.

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Korolek [52]

Answer: there is zero kinetic energy but there is Gravitational Potential Energy (GPE) and GPE = 8826.3 J

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3 0
3 years ago
How much power does a 2000 kg car need to accelerate from 20 m/s to 35 m/s in 7 seconds?
Alexus [3.1K]

firstly you get your acceleration with the formula, a=v-u/t. Then you use the formula for kinetic energy 1/2mv^2

then you can finally get the answer for power by dividing your previous answer by the time

3 0
3 years ago
At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v
Anna007 [38]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For this purpose we will define the speed as the distance traveled in a given period of time. Here the distance is equivalent to the orbit traveled around the earth, that is, a circle. Approaching the height of the aircraft with the radius of the earth, we will have the following data,

R= 6370*10^3 m

v = 219m/s

a = 17m/s^2

The circumference of the earth would be

\phi = 2\pi R

Velocity is defined as,

v = \frac{x}{t}

t = \frac{x}{v}

Herex = \phi, then

t = \frac{\phi}{v} = \frac{2\pi (6370*10^3)}{219}

t = 1.82*10^5s

Therefore will take 1.82*10^5 s or 506 hours, 19 minutes, 17 seconds

3 0
3 years ago
A 30 g horizontal metal bar, 13 cm long, is free to slide up and down between two tall, vertical metal rods that are 13 cm apart
natita [175]

Answer:

Terminal speed, v = 6901.07 m/s

Explanation:

It is given that,

Mass of the horizontal bar, m = 30 g = 0.03 kg

Length of the bar, l = 13 cm = 0.13 m

Magnetic field, B=5.5\times 10^{-2}\ T

Resistance, R = 1.2 ohms

We need to find the terminal speed oat which the bar falls. When terminal speed is reached,  

Force of gravity = magnetic force

mg=ilB..................(1)

i is the current flowing

l is the length of the rod

Due to the motion in rods, an emf is induced in the coil which is given by :

E=Blv, v is the speed of the bar

iR=Blv

i=\dfrac{Blv}{R}

Equation (1) becomes,

mg=\dfrac{B^2l^2v}{R}

v=\dfrac{mgR}{B^2l^2}

v=\dfrac{0.03\times 9.8\times 1.2}{(5.5\times 10^{-2})^2(0.13)^2}

v = 6901.07 m/s

So, the terminal speed at which the bar falls is 6901.07 m/s. Hence, this is the required solution.

5 0
3 years ago
M A sinusoidal wave on a string is described by the wave function
IceJOKER [234]

The frequency of the wave is determined as 7.96 Hz.

<h3>Frequency of the wave</h3>

The frequency of the wave is calculated as follows;

y = A sin(ωt - kx)

where;

  • A is amplitude of the wave
  • ω is angular speed of the wave

ω = 2πf

f = ω/2π

f = (50)/(2π)

f = 7.96 Hz

Thus, the frequency of the wave is determined as 7.96 Hz.

Learn more about frequency of waves here: brainly.com/question/6297363

#SPJ4

5 0
2 years ago
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