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Olin [163]
3 years ago
13

What is a solution?

Chemistry
1 answer:
Marizza181 [45]3 years ago
7 0

A solution is a homogeneous type of mixture of two or more substances. A solution has two parts: a solute and a solvent.

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_____ are factors that are not tested and remain constant. A. Dependent variables B. Controlled variables C. Independent variabl
stepan [7]

Answer:

B. Controlled variables

Explanation:

The Dependent sample t-test compares the mean score of measurements in one group to that of another other group. It mainly used when analyzing comparable sample units as it pairs repeatable observations within a time frame.

Controlled variables are factors that are not tested and remain constant. Some examples of controlled variables are temperature, pressure, volume etc

5 0
3 years ago
Con los siguientes elementos: 37Rb 33As 52Te 1H 8O 56Ba 53I forme seis compuestos con enlace iónico. Debe hacer la representació
elena-14-01-66 [18.8K]
Los electrones los representa Lewis
8 0
4 years ago
Write balanced molecular, ionic, and net ionic equations for the reaction occurs when (a) a BaCl2 (Barium Chloride) is mixed wit
lubasha [3.4K]

A.) We write the molecular equation for the chemical reaction as:

BaCl2(aq)+Na2SO4(aq)→BaSO4(s)⏐+2NaCl(aq)

Alternatively, we could write the net ionic equation:

Ba2+ + SO2^−4→ BaSO4(s)⏐

B.)We write the molecular equation for the chemical reaction as:

Ba(OH)^2 + 2HBr → BaBr2 + 2H2O

The ionic equation can be written as;

Ba^2+ + 2OH^- + 2H^+ + 2Br^- →

Ba^2+ + 2Br^- + 2H2O

the net ionic equation can be written as;

2OH^- + 2H^+ → 2H2O

Alternatively, we could write the net ionic equation

OH^-(aq) + H^+(aq) → H2O(l) net ionic equation.

C.) We write the molecular equation for the chemical reaction as:

2 HNO2(aq) + Ba(OH)2(aq) 

→ Ba(NO2)2(aq) + 2 H2O(l)

Net ionic equation

HNO2(aq) + OH-(aq) → NO2-(aq) + H2O(l)

Alternatively, we could write the net ionic equation as:

2H^+ + 2OH → 2H2O

8 0
4 years ago
. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyana
fenix001 [56]

The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg

<h3>Stoichiometric problem</h3>

From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.

Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles

Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles

Equivaent mole of carbon dioxide = 736.84/2 =368.42moles

Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg

Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

5 0
2 years ago
a reaction in which one element replaces another on a compound or in which two elements in different compounds trade places is c
lilavasa [31]
Single Replacement and Double Replacement reactions
5 0
4 years ago
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