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adell [148]
3 years ago
10

What type of wave is a s-wave and how does energy move through the wave

Chemistry
1 answer:
Blizzard [7]3 years ago
3 0
In S or shear waves, rock oscillates perpendicular to the direction of wave propagation.
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What is the diet of sloth bears ?​
Svetllana [295]
This is what I got hope it helps

4 0
3 years ago
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Which of the following aqueous solution will have the highest boiling point
Sliva [168]

Ionic molecules have higher boiling point than covalent molecules.

So that leaves Na2SO4 and NaCl.

The ionic molecule with higher charge will have higher boiling point.

Na2SO4 have ions with charge +-2.

NaCl have ions with charge +-1.

So the answer is C.

4 0
3 years ago
How many atoms of fluorine are in 5.6×1022 molecules of MgF2?
VashaNatasha [74]

Answer:You can set up stoichiemetry using the following equation:

(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)

= 3.03 x 10^23 molecules of F

or 1.52 x 10^23 molecules of F2

The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.

The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.

One mole of a gas has 6.02214179*10^23 particles.

15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.

(15.6/62.3018)*6.02214179*10^23

=> 1.5079*20^23

If this is rounded to one decimal figure the result is 1.51*10^23.

The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.

3 0
3 years ago
If a hydrogen atom and a helium atom have the same kinetic energy:________
Nuetrik [128]

Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

Explanation:

The relation between energy and wavelength is as follows.

E = \frac{hc}{\lambda}\\

This means that energy is inversely proportional to wavelength.

As it is given that energy of a hydrogen atom and a helium atom is same.

Let us assume that E_{hydrogen} = E_{helium} = E'. Hence, relation between their wavelengths will be calculated as follows.

E_{hydrogen} = \frac{hc}{\lambda_{hydrogen}}    ... (1)

E_{helium} = \frac{hc}{\lambda_{helium}}         ... (2)

Equating the equations (1) and (2) as follows.

E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'

Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

7 0
3 years ago
The alternative pathways of photosynthesis using the c4 or cam systems are said to be compromises. why?
frosja888 [35]
 It is because C4 compromises on water loss and CAM compromises on photorespiration. and Both minimize photorespiration but expend more ATP during carbon fixation. 
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