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melomori [17]
2 years ago
7

What happens during radioactive decay?

Chemistry
2 answers:
GenaCL600 [577]2 years ago
5 0

Answer:

When a radioactive atom undergoes a nuclear decay event (the significant decay modes are alpha decay, beta decay, electron capture, and spontaneous fission), the decaying nucleus undergoes a transformation in identity associated with the change in the number of protons in the nucleus

timama [110]2 years ago
5 0
The answer would be A
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A. They have similar DNA
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How are radioisotopes different from the standard form of an element
meriva

Answer:

Different isotopes of the same element have the same number of protons in their atomic nuclei but differing numbers of neutrons. Radioisotopes are radioactive isotopes of an element. They can also be defined as atoms that contain an unstable combination of neutrons and protons, or excess energy in their nucleus.

6 0
3 years ago
which method would be best for separating the compounds of a mixture that is made from two diffrent liquids
kobusy [5.1K]

Answer:

fractional distillation since ot depends on the different liquids to have different boiling points

5 0
2 years ago
The electron configuration of an element is 1s22s22p63s1. Describe what most likely happens when an atom of this element comes n
bearhunter [10]

Answer:

The element with electron configuration 1s² 2s² 2p⁶ will most likely not........

Explanation:

5 0
2 years ago
Determine the LIMITING reactant in the following balanced equation:
padilas [110]

Answer:

KBr is limiting reactant.

Explanation:

Given data:

Mass of  KBr =4g

Mass of Cl₂ = 6 g

Limiting reactant = ?

Solution:

Chemical equation:

2KBr + Cl₂      →    2KCl + Br₂

Number of moles of KBr:

Number of moles = mass/molar mass

Number of moles = 4 g/ 119 gmol

Number of moles = 0.03 mol

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 6 g/ 70 gmol

Number of moles = 0.09 mol

Now we will compare the moles of reactant with product.

              KBr            :            KCl

                2              :              2

            0.03            :            0.03

             KBr            :              Br₂

                2             :               1

             0.03           :          1/2×0.03= 0.015

               Cl₂             :            KCl

                 1              :              2

            0.09            :           2/1×0.09 = 0.18

               Cl₂             :              Br₂

                1              :               1

             0.09           :            0.09

Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂  is present in excess.

5 0
3 years ago
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